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Paha777 [63]
4 years ago
12

A prism is completely filled with 3996 cubes that have edge lengths of  13  in. What is the volume of the prism? Enter your answ

er in the box. in³
Mathematics
2 answers:
bearhunter [10]4 years ago
5 0

The anser is 148 I took the test

ANEK [815]4 years ago
3 0
First, solve for the volume of each cube through the equation,
                                        V = e³
Substituting the known value,
                                        V = (13 in)³ = 2197 in³
Then, multiply this volume by the number of cubes. Thus, the total volume of the prism,
                                     V = (2197 in³)(3996) 
                                      V = 8,779,212 in³
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for the question. 19. Solve this equation: 80 = 3y + 2y + 4 + 1. A. y = 15 B. y = 75 C. y = –15 D. y = 1/5
Scorpion4ik [409]
80 = 3y+ 2y+4+1
Simplfy like terms:
80 = 5y + 5
-5           -5
75 = 5y
5       5
y = 15 
The answer is A. hope this helps

3 0
3 years ago
Read 2 more answers
Which is greater, 13/35 or 2/5?
zhenek [66]
Hi there!

If you run into problems like this, remember to "Stay calm and find the common denom." That just means find the common denominator.

13/35 and 2/5 = 13/35 and 14/35

As you can tell, 2/5 is larger.

Hope this helps.

:)
5 0
3 years ago
A certain element has a half life of 2.5 billion years. a. You find a rock containing a mixture of the element and lead. You det
sashaice [31]

Answer:

Step-by-step explanation:

For a first order decay, fraction remaining = 0.5n where n = number of half lives elapsed.

fraction remaining = 55% = 0.55

0.55 = 0.5n

log 0.55 = n log 0.5

-0.2596 = -0.301 n

n = 0.8625 = # of half lives elapsed

0.8625 half lives x 2.5 billion years/half live = 2.16 billion years have elapsed = age of the rock

b)  0.15 = 0.5n

log 0.15 = n log 0.5

-0.824 = -0.301 n

n = 2.74 half lives

2.5 billion years/half life x 2.74 half lives = 6.85 billion years = age of rock

7 0
3 years ago
Sea level is considered to be 0 feet. A probe released at sea level dropped at a constant rate for 3.25 minutes, reaching an ele
HACTEHA [7]

d = r * t

d/t = r

-35.75 / 3.25 = r

-11 = r

r = -11 ft / min

d = r*t

d = -11 ft/min * 1 min

d = -11 ft

The probe is 11 feet below sea level after 1 minute

5 0
3 years ago
If 4^x+1 = 64, then what is the value of x^4
Olin [163]
4^{x} + 1 = 64 \\4^{x} = 63 \\ln(4^{x}) = ln(63) \\xln(4) = ln(63) \\x = \frac{ln(63)}{ln(4)}

(\frac{ln(63)}{ln(4)})^{4} = 79.78006702

The value of x⁴ is equal to 79.8006702
7 0
4 years ago
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