Answer:
Nitrogen = 0.3 atm
Oxygen = 0.25 atm
Argon = 0.45 atm
Explanation:
According to Dalton's law of partial pressure, the total pressure in the container is equal to sum of the partial pressures of the individual gases.
Given;
Total pressure of the gases, P_total = 1 atm
Pressure of nitrogen, P_nitrogen = 0.3 atm
Pressure of oxygen, P_oxygen = 0.25 atm
Pressure of argon, P_argon = ?

Therefore, the contribution of each gas to the total pressure of the gas mixture is;
Nitrogen = 0.3 atm
Oxygen = 0.25 atm
Argon = 0.45 atm
Answer:
They have properties of both metals and nonmetals
Explanation:
- Elements in the periodic table may be divided into Metals, non-metals, and metalloids.
- Metals are the elements that react by losing electrons to form stable positively charged ions known as cations. Examples are group 1, 2, and 3 elements together with transition elements.
- Non-metals are those elements that react by gaining electrons to form stable negatively charged ions called anions. Examples include oxygen, carbon, sulfur, etc.
- Metalloids, on the other hand, are elements that have both metallic and non-metallic properties.
- Metalloids occur between metals and non-metals in the periodic table. Examples include Boron and silicon among others.
Small area or region with a relatively hot temperature in comparison to its surroundings.a very hot and dry place where a fire is likely to start, or where a fire has been burning.
Answer : The absolute permeability is, 0.111 darcys.
Explanation : Given,
Volumetric constant rate = 
Cross section area = 
Pressure = 2 atm
Viscosity = 1.0 cp
Length of rock = 4 cm
From the Darcy equation we conclude that,

where,
A = cross section area
P = pressure
= viscosity
l = length of rock
Now put all the given values in the above formula, we get:


Therefore, the absolute permeability is, 0.111 darcys.
PH scale is used to determine how acidic or basic a solution is.
pH can be calculated as follows;
by knowing the ph we can calculate pOH
pH + pOH = 14
pOH = 14 - 8.1
pOH = 5.9
pOH is used to calculate the hydroxide ion concentration
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 1.26 x 10⁻⁶ M
therefore hydroxide ion concentration is 1.26 x 10⁻⁶ M