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Flauer [41]
3 years ago
9

Seawater has a ph of 8.1. what is the concentration of oh–?

Chemistry
1 answer:
lara31 [8.8K]3 years ago
4 0
PH scale is used to determine how acidic or basic a solution is.
pH can be calculated as follows;
by knowing the ph we can calculate pOH
pH + pOH = 14
pOH = 14 - 8.1 
pOH = 5.9 
pOH is used to calculate the hydroxide ion concentration 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 1.26 x 10⁻⁶ M
therefore hydroxide ion concentration is 1.26 x 10⁻⁶ M
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It is necessary to have a 40% antifreeze solution in the radiator of a certain car. the radiator now has 70 liters of 20% soluti
Akimi4 [234]
The answer is : 17.5 liters drained and replaced by 17.5 liters of 100% solution. 
x = amount drained and replaced
(70-x) = remaining amount of 20% solution
<span>.20(70-x) + 1.00(x) = .40(70)
14 - .2x + 1x = 28
1x - .2x = 28 - 14
</span><span>.8x = 14
</span><span>x = 14/.8
x= 17,5 ( 17.5 liters drained and replaced by 17.5 liters of 100% solution)

</span>
6 0
3 years ago
Read 2 more answers
Match each lab incident to the item of PPE that will protect you from it. Each item of PPE will only be used once.
andre [41]

Answer:

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Explanation:

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5 0
3 years ago
1. In which of these forms does acid precipitation reach the surface of<br><br> Earth?
vodomira [7]

Answer:

Wet deposition

Explanation:

when the chemicals produced in the Earth can evaporate and reach the clouds, it will mixed with the water inside the clouds and form a slightly acid water than when is time to deposit the water into the Earth as snow, rain, fog or mist, the chemicals will travel with the water dissolved in it.

When they reach the soil, eventually, the water will  evaporate or will be absorbed by soil, so the chemicals that are left behind, will reach the surface of Earth.

Depending where the chemicals were deposit, they can contaminate the sea, or other water bodies, or soil areas of crops, buildings, etc.

Hope this info is useful.

5 0
3 years ago
At a particular temperature, 12.0 moles of so3 is placed into a 3.0-l rigid container, and the so3 dissociates by the reaction 2
saul85 [17]
            2 SO₃ --> 2 SO₂ + O₂
I             12             0          0
C           -2x           +2x      +x
---------------------------------------------
E         12-2x          2x         x

Since the moles of SO₂ at equilibrium is 3 mol, 2x = 3. Then, x = 1.5 mol. So, the amounts at equilibrium is:
SO₃: 12 - 2(1.5) = 9
SO₂: 2(1.5) = 3
O₂: 1.5

The formula for K basing on the stoichiometric reaction is:
K = [SO₂]²[O₂]/[SO₃]² 
where the unit used is conc in mol/L.

K = [3 mol/3 L]²[1.5 mol/3 L]/[9 mol/3 L]²
<em>K = 0.0556</em>
4 0
3 years ago
How do the equilibrium concentrations of the reactants compare to the equilibrium concentrations of the product?
Scorpion4ik [409]

Answer: It depends equilibrium constant K

Explanation:   You need to to have reaction formula.

If K >> 1 then concentrations of products are much bigger than

concentrations of reactants. If K < < 1, concentration of products is small.

6 0
3 years ago
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