it's either A. or C. because
The answer is C.
This can be concluded by looking at the other answers and eliminating them one-by-one.
Managing (Or conserving) a natural resource means to sustain it and use it as efficiently as possible.
With this in mind, we can look and eliminate certain answers.
A is incorrect because driving a car uses gas, a natural resource. By using as much gas as possible, the resource would be wasted instead of conserved.
B is incorrect because water is a natural resource. Once again, by using this, it's wasted where it could be conserved.
C is correct because planting trees would conserve the resource; by consistently planting trees where they're cut, the chances of running out of wood decrease.
D is incorrect because both the water and the creatures that live inside it are natural resources. By dumping toxic waste, these resources are wasted where it could be conserved.
Hope this helped you! :)
383.5 grams is the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution.
Explanation:
Given that:
Solution to be prepared is 5.5 %
mass of KCl is 22 gram
mass of water required =?
5.5 % solution means that
5.5 grams in 100 ml or gram of water to make solution.
let the water required is 5.5 + x, so the equation will be
5.5 =
x 100
121+ 5.5x = 2200
5.5 x = 2200-121
x = 
x = 378 grams
The mass of water added to KCl to make it 5.5% percent solution is
5.5 +378
= 383.5 grams.
to make the solution of 5.5 percent of KCl weighing 22 grams.
<span>In order convert the mass of a substance to its number of moles The conversion factor is the reciprocal of the molecular weight of the substance. Hence, for the given element in the problem- potassium, the equivalence factor is d. </span><span>(1 mol K/39.10 g K). </span>
<h3>Answer:</h3>
Limiting reactant is Lithium
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of Lithium as 1.50 g
- Mass of nitrogen is 1.50 g
We are required to determine the rate limiting reagent.
- First, we write the balanced equation for the reaction
6Li(s) + N₂(g) → 2Li₃N
From the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
- Second, we determine moles of Lithium and nitrogen given.
Moles = Mass ÷ Molar mass
Moles of Lithium
Molar mass of Li = 6.941 g/mol
Moles of Li = 1.50 g ÷ 6.941 g/mol
= 0.216 moles
Moles of nitrogen gas
Molar mass of Nitrogen gas is 28.0 g/mol
Moles of nitrogen gas = 1.50 g ÷ 28.0 g/mol
= 0.054 moles
- According to the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
- Therefore, 0.216 moles of lithium will require 0.036 moles (0.216 moles ÷6) of nitrogen gas.
- On the other hand, 0.054 moles of nitrogen, would require 0.324 moles of Lithium.
Thus, Lithium is the limiting reagent while nitrogen is in excess.
