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zvonat [6]
3 years ago
6

What event typically causes upwelling?

Chemistry
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

Conditions are optimal for upwelling along the coast when winds blow along the shore. Winds blowing across the ocean surface push water away. Water then rises up from beneath the surface to replace the water that was pushed away. This process is known as “upwelling.”

Explanation:

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Determine the electrical work required to produce one mole of hydrogen in the electrolysis of liquid water at 298°K and 1 atm. T
Ostrovityanka [42]

Explanation:

The given data is as follows.

          \Delta H = 286 kJ = 286 kJ \times \frac{1000 J}{1 kJ}

                            = 286000 J

 S_{H_{2}O} = 70 J/^{o}K,      S_{H_{2}} = 131 J/^{o}K

 S_{O_{2}} = 205 J/^{o}K

Hence, formula to calculate entropy change of the reaction is as follows.

          \Delta S_{rxn} = \sum \nu_{i}S_{i}_(products) - \sum \nu_{i}S_{i}_(reactants)

                     = [(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]

                    = [(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]

                    = 163.5 J/K

Therefore, formula to calculate electric work energy required is as follows.

             \Delta G_{rxn} = \Delta H_{rxn} - T \Delta S_{rxn}

                            = 286000 J - (163.5 J/K \times 298 K)

                            = 237.277 kJ

Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.

6 0
3 years ago
what is the molarity of a RbOH solution if 60.0 mL of the solution is neutralized by 52.8 mL of a 0.5M HCl solution (Hint: Ma x
Dahasolnce [82]
RbOH is a strong base that dissociates completely and HCl is a strong acid that too dissociates completely. the complete reaction between the acid and base is;
RbOH + HCl ---> RbCl + H₂O
stoichiometry of acid to base is 1:1
At neutralisation point
H⁺ mol = OH⁻ mol
mol = molarity x volume 
if Ma - molarity of acid and Va - volume of acid reacted
Mb - molarity of base and Vb - volume of base reacted 
Ma x Va = Mb x Vb
0.5 M x 52.8 mL = Mb x 60.0 mL 
Mb = 0.44 M 
molarity of base - 0.44 M 

7 0
3 years ago
.325 mol KOH to grams
lesya [120]
The answer is 18.23432 grams.

Molar mass of KOH= 56.1056

( \frac{1 mol}{56.1056 grams})  (\frac{.325 mol}{x grams}) = 18.234 grams
5 0
3 years ago
Photographs are taken of falling drops of two different liquids: Liquid X Liquid Y Note: the drops have identical volumes. Notic
aliina [53]

Answer:

See explanation

Explanation:

The reason why the droplets are spherical is  the surface area to volume ratio of the falling droplet in a gravitational field. Recall that a sphere has a small surface area to volume ratio.

Between X and Y, one key difference that will define the rate at which the two drops of liquid falls is the viscosity of the fluid. Since the images were not attached, I can not really tell what liquid droplet is more flatter  than the other.

However, the liquid with a greater surface tension will form larger droplets and experience a greater air resistance as the droplet falls. Hence the less the surface tension, the flatter the droplets. Cohesive forces pull molecules of a liquid droplets inwards leading to a more spherical shape and reducing the surface area. Surface tension is therefore the reason why liquids form droplets.

7 0
2 years ago
An aqueous solution has a hydrogen ion contamination of 1.15x10^-2M (1)What is the hydroxide ion concentration in this solution?
Misha Larkins [42]

Answer:

See explanation

Explanation:

We know that

pH = - log [H^+]

but [H^+] = 1.15x10^-2M

Hence;

pH =  - log(1.15x10^-2)

pH = 1.94

And;

pH + pOH = 14

pOH = 14-pH

pOH = 14 - 1.94

pOH = 12.06

Since;

pOH = - log [OH^-]

hence;

[OH^-] = Antilog (-pOH)

[OH^-] = Antilog (12.06)

[OH^-] = 8.7 * 10^-13 M

8 0
2 years ago
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