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Mnenie [13.5K]
3 years ago
10

Which property is best to use when determining the strength of an ionic bond in a solid? lattice energy conductivity hardness so

lubility
Chemistry
2 answers:
Leona [35]3 years ago
8 0

The property best used when determining the strength of an ionic bond in a solid is:

LATTICE ENERGY

The lattice energy is the energy released during the deposition of gaseous ions of opposite charges. Deposition is the transformation of gas to solid.

Explanation:

The main types of solids are ionic, molecular, covalent, and hard. Ionic solids consist of absolutely and negatively energized ions held concurrently by electrostatic forces; the power of the bonding is indicated in the lattice energy. Ionic solids manage to have high melting points and are fairly hard. lattie energy is a stratagem of the energy received in the crystal lattice of a compound, similar to the energy that would be delivered if the element ions were produced together from infinity.

vovangra [49]3 years ago
3 0
The property best used when determining the strength of an ionic bond in a solid is
LATTICE ENERGY

The lattice energy is the energy released during the deposition of gaseous ions of opposite charges. Deposition is the transformation of gas to solid.
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Which statement is true of phenolphthalein?
Anna007 [38]

The correct option is B.

Phenophtalein is an indicator that is usually used in acid base titration experiments. Indicators are substances that undergo distinct, observable changes when the pH of their solutions change. Indicators exhibit changing of colors depending on the pH of the solution in which they are found. They are usually weak bases and acid which are capable of partial dissociation and formation of ions when dissolved in water. There are different types of indicator and phenophtalein is one of them. Phenophtalein is colorless in acidic solution and pink in basic solutions.

5 0
3 years ago
Read 2 more answers
A quantity of 8.10 × 102 mL of 0.600 M HNO3 is mixed with 8.10 × 102 mL of 0.300 M Ba(OH)2 in a constant-pressure calorimeter of
victus00 [196]

Answer:

22.48°C is the final temperature of the solution.

Explanation:

Heat of neutralization of reaction , when 1 mol of nitric acid reacts= ΔH= -56.2 kJ/mol= -56200 J/mol

Moles (n)=Molarity(M)\times Volume (L)

Moles of nitric acid = n

Volume of nitric acid solution = 8.10\times 10^2 mL= 0.81L

Molarity of the nitric acid = 0.600 M

n=0.600 M\times 0.81 L=0.486 mol

Moles of barium hydroxide = n'

Volume of barium hydroxide solution = 8.10\times 10^2 mL= 0.81L

Molarity of the barium hydroxide= 0.300 M

n'=0.300 M\times 0.81 L=0.243 mol

2HNO_3+Ba(OH)_2\rightarrow Ba(NO_3)_3+2H_2O

According to reaction, 2 mol of nitric acid reacts with 1 mol of barium hydroxide .Then 0.486 mol of nitric acid will react with :

\frac{1}{2}\times 0.486 mol=0.243 mol barium hydroxide.

Heat release when 0.486 mol of nitric acid reacted = Q

= ΔH × 0.486 = -56200 J/mol × 0.486 mol=-27,313.2 J

Heat absorbed by the mixture after reaction = Q' = -Q = 27,313.2 J

Volume of the nitric solution = 0.81 L = 810 mL

Volume of the ferric nitrate solution = 0.81 L = 810 mL

Total volume of the solution = 810 mL + 810 mL = 1620 mL

Mass of the final solution = m

Density of water = density of the final solution = d = 1 g/mL

Mass=density\times Volume

m=1 g/ml\times 1620 ml=1620 g

Initial temperature of the both solution were same = T_1=18.46^oC

Final temperature of the both solution will also be same after mixing= T_2

Heat capacity of the mixture = c = 4.184 J/g°C

Change in temperature of the mixture = ΔT =(T_2-T_1)

Q=mc\Delta T=mc(T_2-T_1)

27,313.2 J= 1620 g\times 4.184 J/g^oC\times (T_2-18.46^oC)

T_2=22.49^oC

22.48°C is the final temperature of the solution.

8 0
3 years ago
Why does water stay separated from certain types of oils? plz explain the certain types of materials that oil has inside of it.
lidiya [134]
Diffrences in density makes them stay seperated.
7 0
3 years ago
Which three elements are liquid at 25 degrees Celsius
KengaRu [80]

Answer:

Bromine and mercury are liquid at room temperature and gallium is liquid when just a little above room temperature. Originally Answered: What are the only two elements that are liquid at 25° C (room temperature)? Mercury and Bromine. Mercury is solid below -38 degrees F (-39C) and Bromine below 19 degrees F (-7.2C).

Explanation:

5 0
2 years ago
Read 2 more answers
HELP PLEASE?
Sati [7]

Here's some background information for the question:

Considering a redox reaction, it's either a gain/lose in oxygen, hydrogen, electron, or the increase/decrease in oxidation numbers. As the reaction given above does not contain any oxygen or hydrogen, plus a few reactants/products involves covalently bonded substances, it's best to solve the question by figuring out their change in oxidation numbers.

Basically, each element in either their compound or in their element itself has an assigned oxidation number. As redox reaction means both oxidation and reduction reaction taking place at the same time, <u>oxidation involves an increase in oxidation number of an element in a substance,</u> while r<u>eduction involves a decrease in oxidation number of an element in a substance.</u>

Speaking of assigning oxidation numbers, these are the rules that will be used in the question (though there are a lot more):

  1. Oxidation number of elements in free state itself is 0 (e.g. Cl2, O2, Cu etc.)
  2. The oxidation number of simple ions (e.g. in ionic compounds) is equal to the charge of the ion itself

Here's the most important part:

Let's look at the equation.

Cl2 (g), is a free element by itself, so the oxidation number for it is 0.

NaBr, Na ion has a charge of 1+ normally, thus Na's oxidation number is +1. (we put the +/- sign in front of the number). Br ion has a charge or 1-, therefore its oxidation number is -1.

NaCl, similar to the one above, Na ion has a 1+ charge, so it's oxidation number is +1. Cl ion has a charge of 1-, so it's oxidation number is -1.

Lastly, Br2, it is a free state element, so Br's oxidation number is 0.

Both Br and Cl has a change in oxidation number in the reaction.

The oxidation number of Br has increased from -1 in NaBr to 0 in Br2, therefore oxidation occurred.

The oxidation number of Cl has decreased from 0 in Cl2 to -1 in NaCl, therefore reduction has occurred.

We can determine this is a redox reaction.

For the second part of the question, we can see bromine has been oxidized while chlorine has been reduced considering their change in oxidation number.

3 0
3 years ago
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