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givi [52]
3 years ago
5

The ability of a substance to dissolve in another at a given temperature and pressure is Select one:

Chemistry
2 answers:
Kobotan [32]3 years ago
7 0
A. Solubility is t<span>he ability of a substance to dissolve in another at a given temperature and pressure</span>ity 
MrMuchimi3 years ago
4 0
<span>The ability of a substance to dissolve in another at a given temperature and pressure is: </span>solubility

Here's my reasoning:

There are two things that make up a solution:

A solute and a solvent.

The solute gets dissolved into the solvent (most likely water).

If you need more info, just comment below. Good luck with your studies! :)
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44.0 g/mol

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A moon would be the correct answer.
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Many substances are soluble in water. Which property of water makes this possible?
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5 0
3 years ago
Calculate the amount of heat needed to boil of benzene (), beginning from a temperature of . Be sure your answer has a unit symb
Pavlova-9 [17]

Answer:

Check explanation

Explanation:

From the question, the parameters given are 64.7g of benzene,C6H6; a starting temperature of 41.9°C and bringing it to 33.2°C.

Molar mass of benzene,C6H6= 78.11236 g/mol.

Things to know: heat capacity of benzene, C6H6= 1.63 J/g.K, the heat of fusion = 9.87 kj/mol.

STEP ONE(1): ENERGY USED IN MELTING BENZENE SOLID.

Using the formula below;

Energy used in melting the solid(in JOULES) = (mass of benzene/molar mass of benzene) × heat of Fusion.

=(64.7 g of C6H6/ 78.11236(g per mol) of C6H6) × 9.87 kJ per mol.

= 8.175 J.

= 0.008175 kJ.

STEP TWO (2): ENERGY OF HEATING THE LIQUID.

It can be calculated from the formula below;

Energy= heat capacity (J/g.K) × mass of benzene× (∆T).

= 1.63 J/g.K × 64.7 × (41.9-33.2).

= 917.5J.

= 0.9175 kJ.

Energy required to boil benzene= Energy required to melt the bezene + energy required for boiling.

= 0.008175+ 0.9175.

= 0.93kJ

Approximately, 1 kJ

8 0
2 years ago
Write the complete balanced equation for the following reaction: S8 + O2 yields SO3
aleksklad [387]
S8 + 12O2 yields 8SO3
3 0
3 years ago
Read 2 more answers
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