1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
givi [52]
4 years ago
5

The ability of a substance to dissolve in another at a given temperature and pressure is Select one:

Chemistry
2 answers:
Kobotan [32]4 years ago
7 0
A. Solubility is t<span>he ability of a substance to dissolve in another at a given temperature and pressure</span>ity 
MrMuchimi4 years ago
4 0
<span>The ability of a substance to dissolve in another at a given temperature and pressure is: </span>solubility

Here's my reasoning:

There are two things that make up a solution:

A solute and a solvent.

The solute gets dissolved into the solvent (most likely water).

If you need more info, just comment below. Good luck with your studies! :)
You might be interested in
What mass of aluminum is needed to produce 0.500 mole of aluminum chloride?
3241004551 [841]

Answer:  " 13.5 g Al " ;

                    →  that is:  "13.5 grams of aluminum."

<u>____________________________</u>

Explanation:

<u>____________________________</u>

<u>Note</u>: What is missing from the question is the "balanced chemical equation" for the "chemical reaction" that contains:

 The reactants:  "aluminum (Al) " ;  and "chlorine (Cl) " ;  and:

 The product:    "aluminum choloride (AlCl₃) " .

____________________________

The "balanced chemical equation" is:

____________________________

        2 Al   +   3 Cl₂   →   2 AlCl₃   ;

_____________________________

<u>Note</u>: The molecular weight of "aluminum (Al)" is:   " 26.98 g /mol " .

____________________________

So:  We call solve using a technique known as:  "dimensional analysis" :

____________________________

  0.500 mol AlCl₃ * (\frac{2mol Al}{2mol AlCl_{3} }) * (\frac{26.98g Al}{1 mol Al}) = ?

____________________________

<u>Note</u>:  The units of "mol AlCl₃" cancel out to "1' ; and:

          The  units of "mol Al" cancel out to "1" ; and we are left with:

____________________________

 " \frac{(0.500 * 2 * 26.98)}{2}   g Al ["grams of aluminum"] ;

____________________________

<u>Note</u>: We can "cancel out the "2's" ; since "2/2 = 1 " ; and we have:

 →  (0.500 * 26.98) g Al ;

    = 13.49 g Al ;

         →  Round to 3 (Three) significant figures;

         →  Since:  "0.500" has 3 (Three) significant figures:

____________________________

   =  13.5 g Al ; that is:  "13.5 grams of aluminum."

____________________________

 Hope this is helpful!  

      Best wishes to you in your academic pursuits—and within the "Brainly" community!

____________________________

3 0
3 years ago
Can anyone help with 5 through 8? Please :(
Aleksandr [31]

Answer:

The answer to your question is below

Explanation:

5)        Fe₂O₃(s)   +  3H₂O   ⇒    2Fe(OH)₃ (ac)        Synthesis reaction

6)        2C₄H₁₀(g)  + 13O₂(g)  ⇒   8CO₂ (g)  +  10H₂O   Combustion reaction

7)         2NO₂ (g)  ⇒   2O₂ (g)  +  N₂ (g)                     Decomposition reaction

8)         H₃P (g) +  2O₂ (g)  ⇒    PO (g)  +   3H₂O  Single replacement reaction

4 0
3 years ago
Write a Balanced Equation <br><br><br><br> H2 + Cl2 --&gt; __HCl
Mariana [72]

Answer:

2HCL

Explanation:

Both the elements have 2 so when placing the 2 infront ,it'll distribute/ apply to both

7 0
3 years ago
Calculate the pH in titration of a weak acid: What is the pH in titration of formic acid (HCHO2, 0.200 M, 100.0 mL) after the ad
ki77a [65]

Answer:

pH = 12.61

Explanation:

First of all, we determine, the milimoles of base:

0.120 M = mmoles / 300 mL

mmoles = 300 mL . 0120 M = 36 mmoles

Now, we determine the milimoles of acid:

0.200 M = mmoles / 100 mL

mmoles = 100 mL . 0.200M = 20 mmoles

This is the neutralization:

HCOOH    +     OH⁻         ⇄        HCOO⁻     +    H₂O

20 mmol       36 mmol             20 mmol

                    16 mmol

We have an excess of OH⁻, the ones from the NaOH and the ones that formed the salt NaHCOO, because this salt has this hydrolisis:

NaHCOO  →  Na⁺  +  HCOO⁻

HCOO⁻  +  H₂O  ⇄   HCOOH  +  OH⁻   Kb →  Kw / Ka = 5.55×10⁻¹¹

These contribution of OH⁻ to the solution is insignificant because the Kb is very small

So:  [OH⁻] =  16 mmol / 400 mL →  0.04 M

- log  [OH⁻]  = pOH →  1.39

pH = 14 - pOH → 12.61

6 0
3 years ago
If the density of lead is 11.342 what would be the volume of a 200.0 g sample of metal
Valentin [98]
The answer would be 17.561cm^3
4 0
4 years ago
Read 2 more answers
Other questions:
  • PLEASE ANSWER THIS QUESTION ASAP 50 POINTS
    14·2 answers
  • What is the least polar solvent /solvent system used to run the tlc?
    12·1 answer
  • Which of the following represents a chemical change. A water to boiled
    13·2 answers
  • Question 26(Multiple Choice Worth 1 points) [01.03]Which of the following statements does not support scientific evidence of the
    5·1 answer
  • Ammonia is produced synthetically by the reaction: 2Fe+3Cl2 --- 2FeCl3
    5·1 answer
  • Do you think the ingredients changing into a cake
    14·1 answer
  • Helppp nowww plsss!!
    7·2 answers
  • Each of the containers below hold 150 mL of the indicated solution at 20 oC. Which one would have the highest rate of vaporizati
    14·1 answer
  • Which property is a chemical property of a substance?
    6·2 answers
  • If 100 ml of 3. 0 m solution were diluted to 250 ml, what would the concentration be?.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!