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4 years ago

A segment that connects two points on a cirle is called a

Mathematics

2 answers:

Ivenika [448]4 years ago

7 0

Answer:

Step-by-step explanation:

Any straight line segment connecting two points on a circle or ellipse is called a chord. Any chord in a circle which has no longer chord is called a diameter, and any segment connecting the circle's center (the midpoint of a diameter) to a point on the circle is called a radius.

Anettt [7]4 years ago

6 0

Answer:

chord

Step-by-step explanation: its a circle not that hard

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Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr

NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Distance between B(0, 5) and C(4, 2):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(0, 5) = (x_1, y_1)$

$C(4, 2) = (x_2, y_2)$

$BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}$

$BC = \sqrt{(4)^2 + (-3)^2}$

$BC = \sqrt{16 + 9} = \sqrt{25}$

$BC = 5 units$

Distance between C(4, 2) and D(1, -2)

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(4, 2) = (x_1, y_1)$

$D(1, -2) = (x_2, y_2)$

$CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}$

$CD = \sqrt{(-3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16} = \sqrt{25}$

$CD = 5 units$

Distance between E(-2, -2) and F(-5, 2):

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-2, -2) = (x_1, y_1)$

$F(-5, 2) = (x_2, y_2)$

$EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}$

$EF = \sqrt{(-3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5 units$

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0

3 years ago

Mrs. Jackson gives the table below to her students. In order for the function to be inear, what must a be and why?

12345 [234]

Hi! what graph? you didn't attach but its okay

8 0

3 years ago

kylee has a coin and a number cube. she flips the coin once and rolls the number cube once. what is the probability that the coi

IceJOKER [234]

Answer:

flip the coin again

Step-by-step explanation:

cuz yes pp poopie

7 0

3 years ago

The cost of carpeting the floor of a room, whose breadth is twice it’s height and length is twice it’s breadth, at the rate of R

Leno4ka [110]

Answer:

The cost of plastering the four wall at the rate of Rs 20 per meter square is Rs 3,543.4

Step-by-step explanation:

Given as :

The cost of carpeting a room = Rs 64,000

The rate of carpeting = Rs 540 m²

The breadth is twice its height

The length is twice its breadth

Let The length = L m

The breadth = B m

The height = L m

So, according to question

L = 2 B and B = 2 H

Now, Area of rectangular carpet = Length × Breadth

Or, A = L × B

Or, A = 2 B × B

∵ The cost of carpeting at the rate of Rs 540 per m² = Rs 64,000

So, area = $\frac{64000}{540}$

Or, 2× B² = 118.518

Or, B² = $\frac{118.518}{2}$

Or, B² = 59.259

I,.e B = $\sqrt{59.259}$ = 7.69 m

The length = 2 B

I.e L = 2 × 7.69 = 15.38 m

and H = $\frac{B}{2}$

I.e H = $\frac{7.69}{2}$ = 3.84 m

So, Length = 15.38 m , Breadth = 7.69 m , height = 3.84 m

∵ The area of four wall = 2× ( Length + Breadth ) × height

or, The area of four wall = 2× ( 15.38 + 7.69 ) × 3.84

Or, The area of four wall = 177.17 m²

Now The rate of plastering the four wall = Rs 20 per square meter

So, The cost of plastering the four wall = area of four wall × rs 20

∴ The cost of plastering the four wall = 177.17 × Rs 20

I.e The cost of plastering the four wall = Rs 3,543.4

Hence The cost of plastering the four wall at the rate of Rs 20 per meter square is Rs 3,543.4 answer

7 0

3 years ago

Write the expression. Then, check all that apply.

liberstina [14]

Answer:

2(n - 6)

Step-by-step explanation:

Difference = n - 6

Twice the Difference = 2(n - 6)

5 0

4 years ago

Read 2 more answers