Here’s the answer. See pictures.
a of 5 is 2.5 b of 5 is 2.5 although 5+5=10 = 2.5×4 =10 (even) x of 5 is odd and y of 5 is even
Therefore, its false;)
Answer:
We have:
x < 4 AND x > a.
if a = 4 and we use an "or" instead of the "and" we have:
x < 4 or x > 4.
This is:
"x is larger than 4 or smaller than 4."
Then the solution of this is all the real numbers except the value x = 4.
The set of solutions can be written as:
{xI x ∈ R \ [4]}
Where this reads:
"x belongs to the set of the reals minus the number 4".
Or we also could write it as:
x ∈ (-∞, 4) ∪ (4, ∞)
Where we have two open ends in the "4" side, so the value x = 4 does not belong to that set.
The LCM of 10 and 14 is 2.
