All categories

2 years ago

Find the missing length of a rectangle with a width of 7b^3 and an area of 77a^8b^8

Mathematics

1 answer:

evablogger [386]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

|2 + 3x| = |4 - 2x|<br> Plz

KiRa [710]

Answer:

3x+2|=lpz(|−2x+4|)

Step-by-step explanation:

4 0

3 years ago

Write an expression that represents the area of a circle with radius 3x^3. (For any circle with radius r, a=π r^2 = π .r .r ^.)

aalyn [17]

9514 1404 393

Answer:

B. 9πx^6

Step-by-step explanation:

Putting the given radius into the area formula gives ...

A = πr^2

A = π(3x^3)^2 = π(3^2)(x^(3·2))

A = 9πx^6

6 0

3 years ago

URGENT!!LAST QUESTION!!!! PLS JUST TAKE A LOOK! EASY BUT I AM DUMB!!!!!! WILL GIVE BRANLIEST!!

Luden [163]

Answer:

x = 28

Step-by-step explanation:

If the quadrilaterals are similar, there is a proportionality among their sides:

The top side in the large figure (70) is to the top side in the small figure (10) in the same ratio as the left side (x) in the large figure is to the left side in the small figure (4). This in math terms is written as:

$\frac{70}{10} =\frac{x}{4}$

We can then solve for the unknown "x" by multiplying both sides by 4:

$\frac{70}{10} =\frac{x}{4}\\\frac{70\,*\,4}{10} =x\\x=28$

4 0

3 years ago

PLEASE HELP!!!

Inessa [10]

Answer:

Step-by-step explanation:

3 0

3 years ago

Which values of x are solutions of the equation below

Mandarinka [93]

Answer:

x = 3.3 and -0.3

Step-by-step explanation:

Given the expression

1/x-4 + x/x-2=2/x^2-6x+8

Find the LCM

x-2+x(x-4)/(x-4)(x-2) = 2/x^2-6x+8

Since the denominator, are the same they cancels out

x +1 + x(x-4) = 2

x+1 + x²-4x = 2

x²-3x + 1 - 2 = 0

x² - 3x - 1 = 0

Factorize

x =3±√9+4/2

x =3±√13/2

x = 3±3.6/2

x= 6.6/2 and -0.6/2

x = 3.3 and -0.3

4 0

3 years ago

Find the missing length of a rectangle with a width of 7b^3 and an area of 77a^8b^8​

Find the missing length of a rectangle with a width of 7b^3 and an area of 77a^8b^8