Given ΔEAB and ΔDCB are two right triangles. The figure has ∠BED≅ ∠BDE. Point B is the midpoint of segment AC.
We have to prove that ΔEAB ≅ ΔDCB
In ΔEAB and ΔDCB
BE=BD (∵∠BED≅ ∠BDE)
AB=BC (given B mid-point)
By RHS congruency rule which states that two right triangles are congruent if the hypotenuse and one side of triangle are respectively equal to the hypotenuse and the corresponding side of the other triangle.
