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fenix001 [56]
3 years ago
12

Create a two-column proof:

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

Proved with RHS congruency rule.

Step-by-step explanation:

Given ΔEAB and ΔDCB are two right triangles. The figure has ∠BED≅ ∠BDE. Point B is the midpoint of segment AC.

We have to prove that ΔEAB ≅ ΔDCB

In ΔEAB and ΔDCB

BE=BD   (∵∠BED≅ ∠BDE)

AB=BC    (given B mid-point)

By RHS congruency rule which states that two right triangles are congruent if the hypotenuse and one side of triangle are respectively equal to the hypotenuse and the corresponding side of the other triangle.

Hence, By RHS rule

ΔEAB ≅ ΔDCB

Hence Proved.

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BabaBlast [244]

Answer:

4.875

Step-by-step explanation:

The mean is the average of all the numbers or all the numbers added up divided by how many numbers so

3+5+2+10+6+3+7+3=39 and there are 8 numbers so

39/8 is 4.875 or 4 7/8

4.875

6 0
3 years ago
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4 0
3 years ago
Make U the subject of the formula <br> D = ut + kt2
natali 33 [55]

Remark

I'm going to interpret this equation as

D = ut + kt²  The only difference is the 2.

Solution

Subtract kt² from both sides.

D - kt² = ut   Now divide by u on both sides.

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The t's cancel out. on the right.  You are left with u on the right.

\dfrac{D - kt^2}{t} =\text{u}


6 0
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