Answer: 36 seconds
Step-by-step explanation:
A: 9, 18, 27, 36
B: 12, 24, 36
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
We have been given a diagram and we need to find the value of arc angle a.
According to one of the circle theorems the angle at the centre of a circle is twice the angle at the circumference subtended by the same arc.
Therefore, arc angle a will be twice of the angle at circumference, that is, 34 degrees.
Therefore, value of angle a is:
Answer:
So x=2.32956156226
Step-by-step explanation:
First subtract 1 on both sides
2^3x=127
Now you can rewrite this as
(2^3)^x
As it still equals the same thing
Now 2^3 is 8
So the equation is now
8^x=127
So we use log formula
log8 127=x
So how many times do we have to multiply 8 by itself to get 127?
The answer is: 2.32956156226
Hope this helps!
