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nasty-shy [4]
3 years ago
10

When you look at a transverse wave, the distance from the baseline to the crest of the wave is called the wave's

Physics
2 answers:
Minchanka [31]3 years ago
7 0

Answer:

Amplitude

Explanation:

Amplitude is the vertical distance between the baseline to the crest or the horizontal diatance between crest and trough of a wave. Trough is the lowest point of the wave hence called the baseline while crest is the highest point of a wave. The horizontal distance between two successive waves is however called the wavelength and the product of wavelength and frequency gives the velocity of the waves. Note that amplitude has no effect on the velocity of the waves.

solniwko [45]3 years ago
5 0

Answer:

Amplitude

Explanation:

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What happens whenever energy is transformed from one form to another?
andriy [413]

Answer:

Energy transformation is when energy changes from one form to another – like in a hydroelectric dam that transforms the kinetic energy of water into electrical energy. While energy can be transferred or transformed, the total amount of energy does not change – this is called energy conservation.

Explanation:

Hope This Helps!!

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3 0
2 years ago
A baseball of mass m = 0.31 kg is spun vertically on a massless string of length L = 0.51m. The string can only support a tensio
natulia [17]

Given data:

* The mass of the baseball is 0.31 kg.

* The length of the string is 0.51 m.

* The maximum tension in the string is 7.5 N.

Solution:

The centripetal force acting on the ball at the top of the loop is,

\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}

For the maximum velocity of the ball at the top of the vertical circular motion,

v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}

where g is the acceleration due to gravity,

Substituting the known values,

\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}

Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.

8 0
1 year ago
A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (
lions [1.4K]

initially, the car is traveling at 5.0 m/s.

so, we know acceleration for changing velocity is :

a = (v-v_{o})/t ..........(i)

where v is the final velocity

v_{o} is the initial velocity

t is the time taken to change velocity

Now, as per the question :

initial velocity, v_{o}=5.0 m/s

final velocity, v =11 m/s

time taken, t = 3 s

putting the values in equation (i),

a = ( 11-5 )/3

a = 2 m/s²

Therefore, a, after 3 s, is  <em>2 m/s².</em>

4 0
1 year ago
\Which are consumers within a spruce-fir forest ecosystem?
lara [203]

The answer is mushroom.

6 0
3 years ago
Read 2 more answers
A car, moving along a straight stretch of highway, begins to accelerate at 0.0323 m/s 2 . It takes the car 63.3 s to cover 1 km.
rosijanka [135]
X=ut+0.5at²
1000 = 63.3u + 0.5 * 0.0323 * 63.3²
u = (1000 - 0.1615*63.3²)/63.3
u = 5.57 m/s

i don't even know if this is correct
7 0
3 years ago
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