The ball may attracted to the magnet.
<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
- From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
- As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
- Steel is a magnetic material.
- Magnetic materials gets attracted to the magnet at both the North and South pole.
- This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.
So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.
Learn more about the bar magnet:
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with a -1 iron charge it becomes an electrode
Answer:
(b) da/√2
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
a. 1000N/C
Explanation:
Data mentioned in the question
Electrical field magnitude = 1000 NC
Perpendicular distance = 0.1 m
Perpendicular distance = 0.2 m
Based on the above information, the electric field is
As we know that
where,
= surface charge density
E = distance from nearby point to sheet i.e be independent
The distance at 0.1 and 0.2, the electric field would remain the same
So,
Based on the above explanation, the first option is correct
