Answer:
Explanation:
We shall represent displacement in vector form .Consider east as x axes and north as Y axes west as - ve x axes and south as - ve Y axes . 255 km can be represented by the following vector
D₁ = - 255 cos 49 i + 255 sin49 j
= - 167.29 i + 192.45 j
Let D₂ be the further displacement which lands him 125 km east . So the resultant displacement is
D = 125 i
So
D₁ + D₂ = D
- 167.29 i + 192.45 j + D₂ = 125 i
D₂ = 125 i + 167.29 i - 192.45 j
= 292.29 i - 192.45 j
Angle of D₂ with x axes θ
tan θ = -192.45 / 292.29
= - 0.658
θ = 33.33 south of east
Magnitude of D₂
D₂² = ( 192.45)² + ( 292.29)²
D₂ = 350 km approx
Tan
The work done by the gravitational force = 0
Given the mass of the box = 40 kg
The box is initially at rest.
Distance moved by the applied force = 5m
Force applied = 130 N
Co-efficient of friction between the box and floor = 0.3
The box is moved only in the horizontal direction by the applied force.
Gravitational force is applied in a direction perpendicular to the applied force. hence it doesn't do any work on the box.
Therefore, the work done by the gravitational force is zero.
Learn more about the gravitational force at brainly.com/question/862529
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Answer:
An echo is formed as a result of reflection of the original sound which returns to the listener. You might have experienced Echo in an EMPTY ROOM but no echo is produced after the room is occupied. To avoid echo from being produced the echo has to be absorbed.
Explanation:
Answer:
gdbenjjd kmnxjnhxhsbusndbuehie
Explanation:
shudhspywnhdbbdhojksc
Do you mean mitosis? If so metaphase.
