Answer:
The torque must be applied to the wheel is 15.7 N-m.
Explanation:
Given that,
Mass of the wheel of cylinder, m = 50 kg
Diameter of the wheel, d = 1 m
Radius, r = 0.5 m
Initial speed off the wheel is 0
Final angular speed of the wheel, 120 rev/min = 12.56 rad/s
Angular displacement, 
The torque is given by :

So, the torque must be applied to the wheel is 15.7 N-m.
I think its D and I just joined but yeah it has to be D is my final answer
<span>Angular speed = total degree / time
As = 360*(2.5) / 3.0 min (60)
As = 900 deg / 180 s
As =5 Degree / second</span>
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