1. There are 41.99 grams in 4.5 moles of sodium fluoride.
2. There are 1.26 moles in 98.3 grams of aluminum hydroxide.
3. There are 5 grams in 0.02 moles of beryllium iodide.
4. There are 0.70 moles in 68 grams of copper (II) hydroxide.
5. There are 0.064 grams in 2.3x10^-4 moles of calcium phosphate.
<u>Answer:</u> The concentration of HBr sample is 0.1025 M
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is HBr
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the concentration of HBr sample is 0.1025 M
Answer:
They are protection from the cell!
Explanation:
They move liquid around the cells and have the same internal structure as each other. They are also found in most microorganisms. Hope this helps :)
Answer:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
The function of HCl is oxidize the gold.
Explanation:
It is possible to balance the reaction seeing each compound as a variable and take an equation for each atom, thus:
Au(s) + HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)
a + b + c = d + e + f
Au: a = d <em>(1)</em>
H: b + c = d + 2f <em>(2)</em>
N: b = e <em>(3)</em>
O: 3b = 2e + f <em>(4)</em>
Cl = c = 4d <em>(5)</em>
Assuming <em><u>a = 1</u></em>:
<em><u>1 = d</u></em> <em>(1)</em>
<u><em>c = 4</em></u> <em>(5)</em>
b + 3 = 2f <em>(2)</em>
3b = 2e + f <em>(4)</em>
As b = e:
b = f <em>(4)</em>
<em><u>f = 3</u></em>; <em><u>b = 3</u></em>; <em><u>e = 3</u></em>
Thus, balanced reaction is:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
<em>The function of HCl is oxidize the gold</em> that before reaction is Au⁰ and afte ris Au⁺³
I hope it helps!