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2 years ago

Which phrase defines complementary goods?

Chemistry

1 answer:

Andrew [12]2 years ago

7 0

Answer:

goods used in combinations with other products

Explanation:

its a

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How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?

weeeeeb [17]

Answer : The number of moles of solute $Ca(OH)_2$ is, 0.0788 moles.

Explanation : Given,

Molarity = 0.225 M

Volume of solution = 0.350 L

Formula used:

$\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}$

$\text{Moles of }Ca(OH)_2=0.0788mol$

Therefore, the number of moles of solute $Ca(OH)_2$ is, 0.0788 moles.

7 0

3 years ago

Copper metal has a specific heat of 0.385 J/goC. Calculate the amount of heat required to raise the temperature of 22.8 g of Cu

Liula [17]

Answer is equal to 7.51 kJ

Q=mc(delta)T

4 0

2 years ago

Which of the following would heat up the quickest?

zysi [14]

Answer:

mercury( specific heat=0.140j/gc)

6 0

3 years ago

Nuclear decay<br>27Al + He 》 39P<br>

dybincka [34]

Answer:

$_{13}^{27}\text{Al} + \rm _{2}^{4}\text{He} \longrightarrow \, _{15}^{31}\text{P}$

Explanation:

The unbalanced nuclear equation is

$^{27}\text{Al} + \rm \text{He} \longrightarrow \, ^{31}\text{P}$

We can insert the subscripts, because these are the atomic numbers of the elements

$_{13}^{27}\text{Al} + \, \rm _{2}\text{He} \longrightarrow \, _{15}^{31}\text{P}$

That leaves only the superscript of He to be determined,

The main point to remember in balancing nuclear equations is that the sums of the superscripts must be the same on each side of the equation.

Then

27 + x = 31, so x = 31 - 27 = 4

Then, your nuclear equation becomes

$_{13}^{27}\text{Al} + \, \rm _{2}^{4}\text{He} \longrightarrow \, _{15}^{31}\text{P}$

6 0

3 years ago

Please help.

Anna35 [415]

Answer:

9429.9

Explanation:

periodt

4 0

3 years ago