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4 years ago

13

i want someone to help me about how to get back to study math after 3years of stop studying plz anyone i don't go to school cand

I'm 20 years old

1 answer:

lesya692 [45]4 years ago

3 0

Answer:

U can install educational app.like midaseclass,photo math.

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How do you solve for the central area of a polygon?

ycow [4]

Getting the central area of a polygon is not possible. Probably the question refers to the central angle. In a a regular polygon, getting the central angle is that you need to use the formula.

Central Angle of a polygon = 360 degrees / number of sides of a polygon.
Why 360 degrees? Because, a circle has a total of 360 degrees. And a circle is a polygon with no sides.

5 0

3 years ago

The midpoint of AB is (3,2). If point is is located at(8,4) what are the coordinates of point B

Dmitry [639]

Step-by-step explanation:

8-3 = 5,

3-5 = -2 = the x coordinate of B

-2-4 =-6,

-2-6 =-8 = the y coordinate of B

(-2,-8) is the point B

A is 5 to the right of the midpoint, so B is 5 to the left of the midpoint

A is 6 up from the midpoint so B is 6 down from the midpoint

7 0

2 years ago

A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the

EastWind [94]

Answer:

a) $\hat p=\frac{471}{1024}=0.460$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Data given and notation

n=1024 represent the random sample taken

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

$\hat p=\frac{471}{1024}=0.460$ estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

Part b

If we replace the values obtained we got:

$0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429$

$0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491$

The 99% confidence interval would be given by (0.429;0.491)

8 0

3 years ago

25 x 170 x 6.350<br> please help

m_a_m_a [10]

Answer:

26,987.5

Step-by-step explanation:

hope it's helpful to you ☺️

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8 0

3 years ago

Read 2 more answers

What is 2/25 of 150????

forsale [732]

12, because 150/25=6x2 is 12

7 0

4 years ago