A protist has a nucleus inside of it to make it a Eukaryote, if it had no nucleus it would be consider a Prokaryote
Here is your answer......
Explanation:
Monotremes are mammals that lay eggs. Monotremes are warm blooded with a fast metabolism. They have hairy bodies to keep warm.
Marsupials are mammals that give birth to live young. These mammals have a pouch where their young grow and develop. Marsupials are hairy, warm blooded, and produce milk. One of the biggest differences between marsupials and placental mammals is that marsupials give birth quite early and rely less on the nourishment of the placenta. Some examples of marsupials are kangaroo and opossums.
Placental mammals are mammals that give birth to fully developed live young. They differ from marsupials in that the baby spend more time being nourished in-utero by the placenta. These mammals are hairy and warm blooded as well. Some examples are mice, rats, and bats
Hope it helps.....
<span>#1) With reference to the role of oncogenes, explain how the normal controls over the cell cycle can be lost.
Answer: The way that cell cycle can be lost is by going through changes in the activity of cell cycle regulators. Cancer causes different types of mutations. There are two types of cell cycle regulators that can promote the development of cancer:
-Positive Regulators that can be over activated (become oncogenic).
-Negative Regulators (tumor suppressors) which can be inactivated.
I hope it helps, Regards. <span /><span>
</span></span>
The two are potassium and rubidium. Why? Na is an alkali metal. As you go down the metals become more reactive.
Calcium has 20 protons. Why? The atomic # is 20 (the one at the top).
It has 20 neutrons. Why? The atomic mass (the number on the bottom) is ~40, ignoring electron mass. 40- 20 protons = 20 neutrons.
It has 20 electrons.
Why? The # of protons and electrons is the same. Ions aren't on the periodic table.
Please mark brainliest if I helped you!
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.