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Brums [2.3K]
3 years ago
14

From past results, a professor knows that the test score of a student taking her final examination is a random variable with mea

n 65 and a variance known to be 15. What is the probability that a student will score between 50 and 80? (7-8.1.2)
(A) Somewhere between 0.75 and 0.85
(B) Exactly 0.6826
(C) Exactly 0.9333
(D) Somewhere between 0.55 and 0.75
Mathematics
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

option B

Step-by-step explanation:

Given,

mean result (μ) = 65

standard deviation (σ)= 15

probability that student will score between 50 and 80

= P(50< x

= P(50< x

= P(50< x

 = P(Z < 1) - P(Z < -1)

Using z table,  

= 0.8413 - 0.1587

= 0.6826

the correct answer is option B

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The question states:

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This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

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