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dangina [55]
3 years ago
10

18) Test the equation for symmetry with respect to the x-axis, the y-axis, and the origin.

Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0

Answer:

x-axis only.

Step-by-step explanation:

2x = 5y2 - 3

Convert to vertex form:

x = 5/2 y^2 - 3/2

This is a parabola  with axis of symmetry  y = 0. The vertex is at (-3/2, 0) and it opens to the right.

The axis of symmetry is the x-axis ( y = 0).

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Lesson 7 Practice Problems
zlopas [31]

Answer:

6:22,10:110,9:33

Step-by-step explanation:

all the answers are factors of 3 and 11

6 0
3 years ago
4) (Assume AR is tangent)<br>Given: AR 12<br>SR - 7.7<br>Find: cs (Round to nearest tenth.)​
andreev551 [17]

The length of CS is 11.0

Explanation:

Given that the length of the tangent AR is 12

The length of SR is 7.7

To find: The length of CS

The<u> tangent secant theorem</u> states that "if a tangent and a secant are drawn from an external point to a circle, then the square of the measure of the tangent is equal to the product of the measures of the secant’s external part and the entire secant."

Applying the tangent secant theorem, we have,

AR^2=SR\times RC

Rewriting the above equation, we get,

AR^2=SR(SR+SC)

Substituting the values, we get,

12^2=7.7(7.7+CS)

Simplifying, we have,

144=59.29+7.7CS

Subtracting both sides by 59.29, we get,

84.71=7.7CS

Dividing both sides by 7.7, we have,

11.0013=CS

Rounding off to the nearest tenth, we get,

11.0=CS

Thus, the length of CS is 11.0

6 0
3 years ago
3х2 – 10x+7<br> Factor each trinomial
Archy [21]

Answer:

324

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
18. Let z = a + bi represent a general complex number. As noted in the lesson, the conjugate of z, abbreviated conj(z) or conj(a
AnnyKZ [126]

Question (18):

Answer: (A) All of the following

(I am using z^* in place of conj(z)

z*z^*=(a+ib)(a-ib)=a^2-(ib)^2= a^2+b^2=\mbox{modulus(z)}^2

z+z^*=a+ib+a-ib=2a\\z-z^*=a+ib-a+ib=2bi


Question (19):

Answer: (B) -7

modulus of -7 is sqrt(49)=7

the other choices are all < 7


5 0
3 years ago
The gcf of two numbers less than or equal to 12 is 2. Their LCM is 20.What are the numbers?
bixtya [17]

We know:

LCM(a,\ b)=\dfrac{ab}{GCF(a,\ b)}

We have

GCF(a,\ b)=2,\ LCM(a,\ b)=20,\ a\leq12,\ b\leq12

Substitute:

20=\dfrac{ab}{2}\qquad|\cdot2\\\\ab=40

40=1\cdot40=2\cdot20=4\cdot10=5\cdot8

Only 4 and 10 meet the requirements of the question.

--------------------------------------------------------------------

40 and 1 NOT, because 40 > 12

20 and 2 NOT, because 20 > 12

5 and 8 NOT because GCF(5, 8) = 1

5 0
3 years ago
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