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Anna11 [10]
3 years ago
8

Henry has a new album for his baseball cards. He uses pages that hold 6 cards and pages that hold 3 cards. If Henry has 36 cards

, how many different ways can he put them in his album? Henry can put the cards in his album Ways.
Mathematics
1 answer:
larisa86 [58]3 years ago
6 0
Answer=7 possibilities, assuming that the order in which they are put in isn't a factor.
Possibillities:
1.  6*6=36
2.  (6*5)+(3*2)=36
3.  (6*4)+(3*4)=36
4.  (6*3)+(3*6)=36
5.  (6*2)+(3*8)=36
6.  6+(3*10)=36
7.  3*12=36

7 different ways
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Pringles is planning their sales force spending for the next year. Each of their sales people spends about 3400 hours annually a
LUCKY_DIMON [66]

Answer:

459 sales people.

Step-by-step explanation

Time per call (t) = 45 min = 0.75 h

Hours per sales person (H) = 3,400 hours

Number of customers (n) = 40,000 customers

Call frequency (f)= 52 calls per year

The total number of sales people (S) needed, is given by the total time spent on calls for the year, divided by the amount of hours each person spends on sale:

S=\frac{40,000*0.75*52}{3,400}\\ S=458.8

Rounding up to the next whole person, Pringles needs 459 sales people.

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3 years ago
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3 years ago
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Lynna [10]

Answer:

He would need to walk the dog 6 more times because 8 times 11 is 88 and if he has already walked the dog 5 times you would subtract that from 11 to get 6. So the answer would be 6

Step-by-step explanation:

8·11= 88

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5 0
3 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

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