Answer: Hello mate!
in the store, there are 11 puppies, and 3 of them are poodles.
If Rebbeca and Aaron chose at random, then the probabilities are; for Rebbeca, there is a 3/11 probability to get a poodle ( because there are 3 poodles of eleven dogs) and the probability for Aaron is 2/10 because now there are one less poodle (and in consequence one less puppy)
now, the joint probability of these two events happening is the product of each probability, this is:
p = (3/11)*(2/10) = 6/110, that we can simplify at 3/55 if we divide both denominator and numerator by 2.
If the dog is replaced after Rebbeca picked hers, then Aaron also has a 3/11 probability of picking a poodle, and in that case, the joint probability is:
q = (3/11)*/3/11) = 9/121
now, p = 3/55 = 0.055 and q = 9/121 = 0.074
this means that the probability of both of them selecting a poodle is bigger when the dog is replaced (which makes a lot of sense)
