Answer:
11x^(2) - 3
Step-by-step explanation:
Remove the parentheses: (a)=a
=5x^2-7x+10+7x^2-11-x^2+7x-2
Group the like terms:
=5x^2+7x^2-x^2-7x+7x+10-11-2
Add the similar elements : 5x^2+7x^2-x^2=11x^2
=11x^2-7x+7x+10-11-2
Continue to add similar elements: -7x+7x=0
=11x^2+10-11-2
Then add or subtract the numbers: 10-11-2=-3
<u>FINAL ANSWER</u>:= <em>11x^(2)-3</em>
Let's define the vectors:
U = (4.4)
V = (3.1)
The projection of U into V is proportional to V
The way to calculate it is the following:
Proy v U = [(U.V) / | V | ^ 2] V
Where U.V is the point product of the vectors, | V | ^ 2 is the magnitude of the vector V squared and all that operation by V which is the vector.
We have then:
U.V Product:
U.V = (4,4) * (3,1)
U.V = 4 * 3 + 4 * 1
U.V = 12 + 4
U.V = 16
Magnitude of vector V:
lVl = root ((3) ^ 2 + (1) ^ 2)
lVl = root (9 + 1)
lVl = root (10)
Substituting in the formula we have:
Proy v U = [(16) / (root (10)) ^ 2] (3, 1)
Proy v U = [16/10] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = (4.8, 1.6)
Answer:
the projection of (4,4) onto (3,1) is:
Proy v U = (4.8, 1.6)
500t represents the number of times bees visit the flower because if bees visit the flower 500 times for every year it is alive, and it was alive 5 years, then it would be 500 times 5. So 500t represents how to find how many times a bee would visit a particular plant.
In the form
... y = a(x - h)2 + v
the vertex coordinates are (h, v). These are given in your problem statement as (2, -2).
h = 2
v = -2
A bag contains 10 tiles with the letters A, B, C, D, E, F, G, H, I, and J. Five tiles are chosen, one at a time, and placed in a
lora16 [44]
I assume in this item, we are to find at which step is the mistake done for the calculation of the unknown probability.
For the possible number of arrangement of letter, n(S), the basic principles of counting should be used.
= 10 x 9 x 8 x 7 x 6 = 30,240
This is similar as to what was done in Meghan's work.
For the five tiles to spell out FACED, there is only one (1) possibility.
Therefore, the probability should be equal to 1/30,240 instead of the 1/252 which was presented in the steps above.
