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3 years ago

Please explain the steps to this problem

Mathematics

1 answer:

crimeas [40]3 years ago

5 0

Make the denominators the same number. Then do the problem as you would regularly without fractions

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Daniel calculated that the circumference of his motorcycle tire is 62.8 inches. What is the tire's radius? Use 3.14 for pi.

Savatey [412]

R=19.98 In by dividing

6 0

3 years ago

When the transmogrifiers are made at the factory, they move along a conveyer belt. Every 8th transmogrifier gets a blue control

MaRussiya [10]

Answer:

Blue - 18, green - 50, with photo - 37

Step-by-step explanation:

<u>Total number = 150</u>

Blue = 150/8 = 18 (integer part)
Green = 150/3 = 50
Spaceman Spiff autograph = 150/4 = 37 (integer part)

4 0

3 years ago

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please help :{ brainliest if you can get it right and I need you to prove why your answer is correct, thanksss

beks73 [17]

Answer:

The Value of $a=\frac{15}{4}$ .

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

RS = b

PS = z

PQ = x

QS = 15

∠P = 90°

∠R = 90°

∠Q = 60°

∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

∠S = 30°

Now we know that;

$sin\ \theta = \frac{opposite\ side}{Hypotenuse}$

$sin \ S= \frac{PQ}{QS}$

Substituting the given values we get;

$sin\ 30\°=\frac{x}{15}$

Now we know that;

$sin\ 30\° = \frac12$

So we can say that;

$\frac{1}{2}=\frac{x}{15}\\\\x=\frac{15}{2}$

Now In Triangle PQR.

∠R = 90°

∠Q = 60°

So we can say that;

$Cos \theta = \frac{adjacent \ Side}{Hypotenuse}\\$

$Cos\ Q = \frac{QR}{PQ}$

Substituting the given values we get;

$cos 60\°= \frac{a}{x}$

Now we know that;

$cos 60\°= \frac12$

$x=\frac{15}{2}$

So substituting the values we get;

$\frac{1}{2}=\frac{a}{\frac{15}{2}}$

By Using Cross Multiplication we get;

$a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}$

Hence The Value of $a=\frac{15}{4}$ .

6 0

3 years ago

What is the range of y = sinx in the interval - π ≤ x ≤ 0?

Kaylis [27]

Answer:

$-1 \le y \le 1$

Step-by-step explanation:

Let be $y = \sin x$ , the range of the function corresponds to the set of values of $y$ . The sine function is a bounded function between -1 and 1. Hence, the range of the function is:

$-1 \le y \le 1$

6 0

3 years ago

100 POINTS PLEAS please help

Kamila [148]

Answer:

$\textsf{A)} \quad 5u^3-2u^2+5u+8$

Step-by-step explanation:

Given expression:

$(-2u^3+5u-1)+(7u^3-2u^2+9)$

Remove parentheses:

$\implies -2u^3+5u-1+7u^3-2u^2+9$

Collect like terms:

$\implies -2u^3+7u^3-2u^2+5u-1+9$

Combine like terms:

$\implies 5u^3-2u^2+5u+8$

6 0

2 years ago

Read 2 more answers