Answer:
Step-by-step explanation:
(jk^-2/j^-1k^-3)^3
(-2)(-1)^-2
------------- ^3
(-2)^-1(-1)^-3
switch negative exponenst to other side
(-2)(-2)(-1)^3
__________
(-1)^2
4(-1)
-----
1
= -4
REMEMBER all to the 3rd power!
(-4)^3
-64
Answer:
B. y=3(x-1)2 + 3
Step-by-step explanation:
Given that
vertex of the parabola is at the point (1,3)
let's verify, if the option B is the correct equation of the parabola.

comparing to standard equationof parabola (standard quadratic equation), we get

to find the vertex we use formula for x- coordinate as 

to find y put x=1 in the Eq1, we get

vertex =(x,y) = (1, 3)
thus vertex of the parabola from the equation y=3(x-1)2 + 3 is (1,3), thus verified
<em>4x-79=3x-29</em>
<em>Move the terms with "x" on the left, and the numbers on the right.</em>
<em>4x-3x=79-29</em>
<em>x=50</em>
Answer:
21 + 3a
Step-by-step explanation:
3 (7+a)
distribute 3 into parentheses:
21 + 3a
Answer:
4. (2, 3)
5. (0, 1)
7. (-1, 2)
Step-by-step explanation:
I hope this helps! Have a nice dayy! :)