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3 years ago

Turn 18/5 into a decimal

Mathematics

2 answers:

Sauron [17]3 years ago

6 0

Your answer is 3.6
you're welcome

lana [24]3 years ago

3 0

18/5 is basically 3 3/5 as a mixed number. When you convert a fraction to a decimal, you always want the denominator to either 10, 100, or 1000 so that the number is accurate. And so you multiply the denominator by what ever number will get 10, 100 or 1000, in which in this case is 10 when you multiply by 2. Multiply the numerator(3) by 2 so that it will be the same value. You should now have 3 6/10. After that, since 6/10 is basically 60/100, take out the 100 and move the decimal unit 2 units to the left of 60. And since you still have the whole number three, your final answer will be 3.6.

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Find the equation of the line that is parallel and passes through the point (9,6) find the equation of the line perpendicular

masya89 [10]

Any line parallel to this line can be written as y=-2/3x+c and passes through (9,6).thus 6=-2/3(9)+c.c-6=6.c=12.equation is y=-2/3x+12.

3 0

3 years ago

Solve the equation for x, where x is a real number (5 points): <br> -5x^2 + 7x + 41 = 32

wel

Subtract 32 to both sides to the equation becomes -5x^2 + 7x + 9 = 0.

To solve this equation, we can use the quadratic formula. The quadratic formula solves equations of the form ax^2 + bx + c = 0
                   x = [ -b ± √(b^2 - 4ac) ] / (2a)
                   x = [ -7 ± √(7^2 - 4(-5)(9)) ] / ( 2(-5) )
                   x = [ -7 ± √(49 - (-180) ) ] / ( -10 )
                   x = [ -7 ± √(229) ] / ( -10)
                   x = [ -7 ± sqrt(229) ] / ( -10 )
                   x = 7/10 ± -sqrt(229)/10
The answers are 7/10 + sqrt(229)/10 and 7/10 - sqrt(229)/10.

6 0

3 years ago

Melanie and Joseph are raising money for their class trip to the zoo. They each need $30 to pay for the trip and are selling box

lisabon 2012 [21]

Melanie needs $18 more dollars. joseph has sold 5 boxes which means he has $20 and melanie has sold 3 which means she has $12 so 30-12=18

4 0

3 years ago

Read 2 more answers

Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo

Shkiper50 [21]

Answer:

a) $P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335$

b) $P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452$

c) $P(X \geq 8) = 1-P(X$

d) $P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that $X \sim Poisson(\lambda=4)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda=4$ , $Var(X)=\lambda=2$ , $Sd(X)=2$

a. Compute both P(X≤4) and P(X<4).

$P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183$

$P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733$

$P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465$

$P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646$

$P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692$

b. Compute P(4≤X≤ 8).

$P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595$

$P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298$

$P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452$

c. Compute P(8≤ X).

$P(X \geq 8) = 1-P(X$

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

$P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

4 0

3 years ago

Help please need help with this stuff thank you again for helping

Alex777 [14]

Slope intercept form: y = mx + b

Where m = slope and b = y-intercept.

By looking at the graph, we can see that the line cuts at 1/2 on the y-axis, therefore eliminating option D.

So now we have: y = mx + 1/2

Next, we'll find the slope. $\frac{y_2-y_1}{x_2-x_1}$

Plug the coordinates into the formula.

$\frac{3-(-2)}{4-(-4)}= \frac{5}{8}$

So our slope is 5/8 and the y-intercept is 1/2.

Option A is the answer.

6 0

3 years ago