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3 years ago

8+(x divided by 3)=-2

Mathematics

2 answers:

KIM [24]3 years ago

8 0

Answer:

x=-6

Step-by-step explanation:

Given: 8+ (x/3)=-2

Step 1: 8+(x/3 times 3) = -2 times 3 which leads to 8+x=-6

Step 2: 8(-8)+x=-6 which leads to x=-6

Answer: x=-6

fenix001 [56]3 years ago

7 0

Answer:

x = -18

Step-by-step explanation:

8 + x/3=-2

3×8+x/3×3=-2×3

24+x=-6

x=-18

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3 years ago

What are the roots of the equation y=x^2 -5x-24

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Factor
(x-8)(x+3)

Check:
-8+3=-5
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Use ZPP
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3 years ago

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

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3 years ago

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Anna35 [415]

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