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Natalka [10]
3 years ago
13

The volume of water and an egg in a graduated beaker is 200mL. After the egg is removed the volume of the water is found to be 1

25mL . What is the volume of the egg in cm ^3
Physics
2 answers:
WITCHER [35]3 years ago
6 0

Answer:

75 cm

Explanation:

The equation would be 200ml -125 ml thus finding the volume of the egg.

dmitriy555 [2]3 years ago
5 0

Answer:

75 cm³

Explanation:

The volume of the egg is equal to the volume of the egg and water minus the volume of the water.

V = 200 mL − 125 mL

V = 75 mL

V = 75 cm³

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Many compounds of living things, such as carbon dioxide, are formed by which kind of bond?
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When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal speed. Once he has reache
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None of the above forces on air drag on him is equal to his weight

Explanation:

In the velocity-time graph,the gradient of the curve where it is flatten shows the parachutist reaches the terminal velocity when it reaches terminal velocity which means the parachutist reaches constant velocity or speed,indicating that the acceleration of free fall(g) is zero.And according to the resultant force formula weight - air drag= mass*acceleration. so when accelerate is zero,resultant force is zero. And hence the equation will be like this: weight= air drag

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the loss of a partical such as a proton as an atom tries to become stable is called A.) an isotope B.) Radioactive decay C.) Rad
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A man jogs at a speed of 1.6 m/s. His dog waits 1.8 s and then takes off running at a speed of 3 m/s to catch the man. How far w
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Answer:

The dog catches up with the man 6.1714m later.

Explanation:

The first thing to take into account is the speed formula. It is v=\frac{d}{t}, where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is d=v\cdot t

Now, the distance equation for the man would be:

d_{man}=v_{man}\cdot t=1.6\cdot t

The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.

d_{dog}=v_{dog}\cdot (t-1.8)=3\cdot (t-1.8)

For a better understanding, at t=1.8 the dog must be in d=0. Let's verify:

d_{dog}=v_{dog}\cdot (1.8-1.8)=3\cdot (0)=0

Now, for finding how far they have each traveled when the dog catches up with the man we must match the equations of each one.

d_{man}=d_{dog}

1.6\cdot t=3\cdot (t-1.8)

1.6\cdot t=3\cdot t-5.4

1.4\cdot t=5.4

t=\frac{5.4}{1.4}

t=3.8571s

The result obtained previously means that the dog catches up with the man 3.8571s after the man started running.

That value is used in the man's distance equation.

d_{man}=1.6\cdot t=1.6\cdot (3.8571)

d_{man}=6.1714m

Finally, the dog catches up with the man 6.1714m later.

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