Two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.
<h3>What are orbitals?</h3>
Orbital is the place around nucleus where mostly the electrons are present. There are four types of orbitals are present, s, p, d, and f.
The orbitals that are formed by the mixing of these orbitals are called hybrid orbitals.
Thus, two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.
Learn more about orbitals
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Answer:
a. R2b = R/4
Explanation:
The total resistance of a metallic wire is given by the following formula:
R = ρL/A
where,
R = Resistance of Wire
ρ = Resistivity of the material of wire
L = Length of Wire
A = Area of Wire = πr²
Therefore,
R = ρL/πr²
for the 1st wire,
radius = r = b
Therefore,
R = ρL/πb² ----------- equation 1
Now, for the second wire,
r = 2b
Therefore,
R2b = ρL/π(2b)²
R2b = ρL/πb²4
using equation 1:
R2b = R/4
therefore, correct option is:
<u>a. R2b = R/4</u>
Answer:
In chemistry and physics, a valence electron is an outer shell electron with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.
Explanation:
Answer:
The volume will not contract to one fourth of the original.
Explanation:
Applying Charles's Law as:
Given ,
V₁ = ?
V₂ = 2 L
T₁ = 5 °C
T₂ = 20 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (5 + 273.15) K = 278.15 K
T₂ = (20 + 273.15) K = 293.15 K
Using Charles law as:
Thus, the volume will not contract to one fourth of the original. (1/4 of 2 L is 0.5 L).
