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3 years ago

9

A substance has a freezing point of -36 degree C and a boiling point of 356 degree C. At what temperature would this substance b

e in its liquid state?

1 answer:

Travka [436]3 years ago

3 0

Answer:

Between -35 degrees C and 355 degrees C

Explanation:

At any temperature between, but not including the freezing and boiling points, the substance would be in its liquid state.

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Frame S' passes frame S in the usual way. Two events are simultaneous in S'.

yuradex [85]

Answer:

c)They can also be simultaneous in S if their separation is zero.

Explanation:

By relativity theory, we can say two events when seen from two different reference frames can only be simultaneous when they are at the same space location and occur simultaneously in at least one reference frame, therefore when Frame S′ usually passes Frame S. Two occurrences in S′ are simultaneous, therefore these occurrences can be simultaneous in S when their separation is 0 (that is they are at the same location)

And therefore option c. If their separation is zero, they can also be simultaneous in S.

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3 years ago

What is the oscillation period of your eardrum when you are listening to the A4 note on a piano (frequency 440 Hz)?

Contact [7]

The period is the inverse of the frequence:

$T=\dfrac{1}{f}=\dfrac{1}{440}=0.0022\overline{72}$

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Soloha48 [4]

Answer:

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Explanation:

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Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular

RUDIKE [14]

Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

initial angular velocity of the electric drill, $\omega _i$ = 5.21 rad/s

angular acceleration of the electric drill, α = 0.311 rad/s²

time of motion of the electric drill, t = 4.13 s

The angular displacement of the electric drill at the given time interval is calculated as;

$\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad$

Therefore, the drill's angular displacement during that time interval is 24.17 rad.

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Two ladders of uniform density and equal mass m are propped up against

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