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Sindrei [870]
4 years ago
5

Which is the equation of a parabola with vertex (0, 0), that opens to the right and has a focal width of 8? a.y^2=8x b.y^2=-8x c

. x^2=8y d. x^2=-8y
Mathematics
2 answers:
dem82 [27]4 years ago
8 0

Answer:

b

Step-by-step explanation:

masya89 [10]4 years ago
5 0

the answer would be 5
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Ierofanga [76]

Answer:

The answer that I got is C I hope I'm right

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If tan x= -4/3 and sin y=-3/5, where x is a second quadrant angle and y is a fourth quadrant angle, find:
Mariulka [41]

Answer:1. -117:125

2.4:3

3.3116:3125

Step-by-step explanation:

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3 years ago
When multiplying more than two integers how can you determine the sign of the product
ycow [4]
When you multiply two numbers, let’s say x and y, there are no negatives, so you know that it is positive. So that means it’s xy. Now, imagine we make that a -x times y. Since there is only 1 negative, it is negative. So that would be -xy. Now, imagine you have -x times -y. Since there are an even number of negatives, they cancel out!! (Magic). So -x times -y is xy.
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3 years ago
Write a number in the blank that makes this question true<br> 43+29=__+60
arsen [322]

Answer:

12

Step-by-step explanation:

If we fill in the blank and solve the equation, both sides will be equal

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6 0
3 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
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