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Ede4ka [16]
3 years ago
13

Why is the motion of simple pendulum not strictly a simple harmonic motion​

Physics
1 answer:
soldi70 [24.7K]3 years ago
6 0
Sin0) is not exactly in the direction of equilibrium position. But the condition of S.H.M. Is restoring force must directed to the equilibrium position in all instant
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Which of the following cannot be determined by analyzing the periodic table?
dybincka [34]

Your answer is C) The year the element was discovered :)

4 0
3 years ago
Read 2 more answers
When does a skydiver achieve terminal velocity? when gravity equals air resistance when gravity is greater than air resistance w
ElenaW [278]

Answer:

when gravity equals air resistance

Explanation:

There are two forces acting on a skydiver falling down:

1) Gravity - this force acts downward, and it is constant during the whole fall, because its magnitude is given by

F=mg

where m is the mass of the skydiver and g the gravitational acceleration. Both quantities are constant, so the force of gravity is constant.

2) Air resistance - this force acts upward, and it is not constant: it is proportional to the velocity of the skydiver

F=kv

where k is a constant and v is the velocity. Therefore, as the skydiver falls down, its velocity increases and the air resistance increases as well.


The equation of forces for the skydiver is therefore:

mg-kv=ma

where a is the skydiver's acceleration. At the beginning of the fall, mg>kv, so the skydiver accelerates towards the ground. However, as he accelerates, the air resistance kv increases, till the moment at which air resistance becomes equal to gravity:

mg=kv

when this condition occurs, then the acceleration becomes zero, so the skydiver no longer accelerates and continues his fall at constant speed. This constant speed is called terminal velocity, and so it occurs when

gravity equals air resistance

3 0
3 years ago
Read 2 more answers
Two isolated copper plates, each of area 0.40 m2, carry opposite charges of magnitude 7.08 × 10-10 C. They are placed opposite e
polet [3.4K]

Answer:

The potential difference between the plates is 8 V.

Explanation:

Given that,

Area of plates = 0.40 m²

Charge q=7.08\times10^{-10}\ C

Distance = 4.0 cm

We need to calculate the electric field

Using for formula of electric field

E=\dfrac{2q}{2\epsilon_{0}A}

Where, q = charge

A = area

Put the value into the formula

E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}

E=200\ V/m

We need to calculate the potential difference between the plates

Using formula of potential difference

V=E\times d

Where, E = electric field

d = distance

Put the value into the formula

V=200\times0.04

V=8\ V

Hence, The potential difference between the plates is 8 V.

3 0
4 years ago
a ball is dropped from rest at a height of 45.0 m above the ground. ignore the effects of air resistance. What is the speed of c
NemiM [27]

So, the final velocity of the ball when it is 10.0 m above the ground approximately <u>26.2 m/s</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. This question uses the principle of final velocity in free fall. Free fall occurs only when an object is dropped (without initial velocity), so the falling object is only affected by the presence of gravity. In general, the final velocity in free fall can be expressed by this equation :

\boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}}

With the following condition :

  • v = final velocity (m/s)
  • h = height or any other displacement at vertical line (m)
  • g = acceleration of the gravity (m/s²)

<h3>Problem Solving</h3>

We know that :

  • \sf{h_1} = initial height = 45.0 m
  • \sf{h_2} = final height = 10.0 m
  • g = acceleration of the gravity = 9.8 m/s²

Note :

At this point 10 m above the ground, the object can still complete its movement up to exactly 0 m above the ground.

What was asked :

  • v = final velocity = ... m/s

Step by Step

\sf{v = \sqrt{2 \times g \times \Delta h}}

\sf{v = \sqrt{2 \times g \times (h_1 - h_2)}}

\sf{v = \sqrt{2 \times 9.8 \times (45 - 10)}}

\sf{v = \sqrt{19.6 \times 35}}

\sf{v = \sqrt{686}}

\boxed{\sf{v \approx 26.2 \: m/s}}

<h3>Conclusion</h3>

So, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.

<h3>See More :</h3>
  • The relationship between acceleration and the change in velocity and time in free fall brainly.com/question/26486625
5 0
2 years ago
If we use 1 millimeter to represent 1 light-year, how large in diameter is the Milky Way Galaxy?
storchak [24]

Answer:

d.100 meters

Explanation:

The diameter of the Milky Way Galaxy is approximately 100,000 light years.

Here we are using 1 millimiter (1 mm) to represent 1 light-year (1 ly). So, we can set the following proportion:

1 mm : 1 ly = x : 100,000 ly

and by finding x, we find the diameter of the Milky Way Galaxy in the scale used:

x=\frac{(1mm )(100,000 ly)}{1 ly}=100,000 mm = 100 m

so the correct answer is

d. 100 meters

4 0
3 years ago
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