Answer:
The image height is 3.0 cm
Explanation:
Given;
object distance,
= 15.0 cm
image distance,
= 5.0 cm
height of the object,
= 9.0 cm
height of the image,
= ?
Apply lens equation;
![\frac{h_i}{h_o} = -\frac{d_i}{d_o}\\\\ h_i = h_o(-\frac{d_i}{d_o})\\\\h_i = -9(\frac{5}{15} )\\\\h_i = -3 \ cm](https://tex.z-dn.net/?f=%5Cfrac%7Bh_i%7D%7Bh_o%7D%20%3D%20-%5Cfrac%7Bd_i%7D%7Bd_o%7D%5C%5C%5C%5C%20h_i%20%3D%20h_o%28-%5Cfrac%7Bd_i%7D%7Bd_o%7D%29%5C%5C%5C%5Ch_i%20%3D%20-9%28%5Cfrac%7B5%7D%7B15%7D%20%29%5C%5C%5C%5Ch_i%20%3D%20-3%20%5C%20cm)
Therefore, the image height is 3.0 cm. The negative values for image height indicate that the image is an inverted image.
Answer:
c) true. With the magnetic field you can determine the Poynting vector and this is equal to the intensity of the wave
Explanation:
An electromagnetic wave carries energy that is given by the vector of poyntíng
S = 1 / μ₀ E x B
The electric and magnetic fields are related
E = c B
Substituting
S = c /μ₀ B² / 2
The two comes from the average value
Let's examine the claims
a) false to determine the wavelength the frequency is needed
b) False. To find the electric field you need the magnetic field
c) true. With the magnetic field you can determine the Poynting vector and this is equal to the intensity of the wave
540 meters should be the answer
mark me brainliest
The answer is C, 50J
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A prolonged blast (lasting at least 4 seconds) from a vessel in the water is a warning to other vessels in the vicinity that there are vessels in the water that may be difficult to see.
Poor visibility could be due to fog. It is also likely that unseen vessels could appear suddenly around turns or bends, and that it ma not be safe to maneuver without colliding with the unseen vessel.
What should you do when you hear a blast?
a. Reply with a blast of your own to warn other vessels.
b. Slow down in order to better deal with low visibility or coming suddenly upon hidden stationary vessels.