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Mrac [35]
2 years ago
14

Explain what happens to the energy of a rock on the edge of a cliff as it falls from the

Physics
1 answer:
dolphi86 [110]2 years ago
3 0

Answer:

A rock sitting on the edge of a cliff. If the rock falls, the potential energy will be converted to kinetic energy, as the rock will be moving. The potential energy decreases as the kinetic energy increases. The potential energy decreases as the kinetic energy decreases.

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What is the rising of rock layers called
Alex777 [14]

The answer of this question is called uplift i.e the rising of rock layers in geology is called uplift.

Uplift is the process in which there will be vertical elevation of earth surface due to various natural processes occurring inside the surface of earth like earth quakes. Sometimes uplift is also caused by the mountain building which hampers the balance of a particular region.

In the process of uplift,the rocks normally metamorphic rocks present underground will be brought up to the earth surface.The enhanced elevation will cause erosion of lot of materials on the surface of earth.


6 0
3 years ago
Read 2 more answers
A student's calculation for the work done on an object is shown.
MissTica

The statement that describes the error in the work is that the distance must be converted to meters (m).

<h3>FORMULA FOR WORK:</h3>

Work can be calculated by using the following formula:

W = F × d

Where;

  • W = work done
  • F = force (N)
  • d = distance (m)

According to this question, the force is given as 140N and the distance is given as 30cm. The force is calculated as follows:

F = 140N × 30cm = 4200J

This calculation is erroneous because the unit of distance should be converted from cm to meters.

Learn more about work done at: brainly.com/question/3902440

4 0
2 years ago
Read 2 more answers
Convection cells in the mantle drive movements of the plates. True or False
nekit [7.7K]

Answer:

True

Explanation:Plates at our planet's surface move because of the intense heat in the Earth's core that causes molten rock in the mantle layer to move. It moves in a pattern called a convection cell that forms when warm material rises, cools, and eventually sink down. As the cooled material sinks down, it is warmed and rises again.

3 0
3 years ago
Light of wavelength 530.00 nm is incident normally on a diffraction grating, and the first‑order maximum is observed to be 33.0∘
GarryVolchara [31]

Answer:

1028 slits/mm

Explanation:

We are given that

Wavelength of light, \lambda=530nm=530\times 10^{-9} m

1nm=10^{-9} m

\theta=33^{\circ}

n=1

We have to find the number of slits per mm are marked on the grating.

We know that

dsin\theta=n\lambda

Using the formula

dsin33^{\circ}=1\times 530\times 10^{-9}

d=\frac{530\times 10^{-9}}{sin33^{\circ}}

d=9.731\times 10^{-7} m

1m=10^{3}mm

d=9.731\times 10^{-7}\times 10^3mm

d=0.0009731mm

Number of slits=\frac{1}{d}

Number of slits=\frac{1}{0.0009731}/mm

Number of slits=1028/mm

Hence, 1028 slits/mm are marked on the grating.

8 0
3 years ago
Read 2 more answers
What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is w
Yanka [14]
<span>1.37 m/s Assuming her initial velocity is totally horizontal and her vertical velocity is only affected by gravity, let's first calculate how much time she has until she reaches the ledge 8.00 m below her. d = 1/2AT^2 8.00m = 1/2 * 9.8 m/s^2 * T^2 Solve for T 8.00 m = 4.9 m/s^2 * T^2 Divide both sides by 4.9 m/s^2 1.632653061 s^2 = T^2 Take square root of both sides 1.277753 s = T So we now know that she has 1.277753 seconds in which to reach a horizontal distance of 1.75 m. So how fast does she need to be going? 1.75 m / 1.277753 s = 1.369592 m/s Since we only have 3 significant figures in our data, round the result to 3 figures giving 1.37 m/s</span>
8 0
3 years ago
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