20 is the atomic number for Calcium.
A) The kinetic energy of an object is given by:
where m is the mass of the object, and v its speed. For the lion in our problem, m=45 kg and v=14.2 m/s, so its kinetic energy is
b) the increase in gravitational potential energy of the lion is given by:
where g is the gravitational acceleration, and
is the increase in altitude of the lion. In this problem,
, so the increase in gravitational potential energy is
c) When the fox reaches the top of the tree, its gravitational potential energy is
As it jumps, its kinetic energy is
So the total mechanical energy of the fox as it jumps is
Answer:
The process by which the balloon is attracted and possibly sticks to the wall is known as static electricity which is the attraction or repulsion between electric charges which are not free to move.
The wall is an insulator.
Explanation:
When a balloon is blown and tied off, and then the balloon is rubbed on the woolly object once in one direction, and the side that was rubbed against the wool is brought near a wall and then released, it is observed that the balloon is attracted to and sticks to the wall. The above observation is due to static electricity.
Static electricity refers to electric charges that are not free to move or that are static. One of the means of generating such charges is by friction. When the balloon is rubbed on the woollen material, electrons are given away to the balloon's surface. Since the balloon is an insulator (materials which do not allow electricity to pass through them easily), the electrons are not free to move. When the balloon is brought near to a wall, there is a rearrangement of the charges present on the wall. Negative charges on the wall move farther away while the positive charges on the wall are attracted to the electrons on the balloon's surface. Because the wall is also an insulator, the charges are not discharged immediately. Therefore, this attraction between opposite charges as well as the static nature of the charges results in the balloon sticking to the wall.
To solve this problem we will apply the concepts related to the intensity included as the power transferred per unit area, where the area is the perpendicular plane in the direction of energy propagation.
Since the propagation occurs in an area of spherical figure we will have to
Replacing with the given power of the Bulb of 100W and the radius of 2.5m we have that
The relation between intensity I and
Here,
= Permeability constant
c = Speed of light
Rearranging for the Maximum Energy and substituting we have then,
Finally the maximum magnetic field is given as the change in the Energy per light speed, that is,
Therefore the maximum value of the magnetic field is
Answer:
B=9.1397*10^-4 Tesla
Explanation:
To find the velocity first we put kinetic energy og electron is equal to potential energy of electron
K.E=P.E
where :
m is the mass of electron
v is the velocity
V is the potential difference
eq 1
Radius of electron moving in magnetic field is given by:
eq 2
where:
m is the mass of electron
v is the velocity
q=e=charge of electron
B is the magnitude of magnetic field
Put v from eq 1 into eq 2
B=9.1397*10^-4 Tesla