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Dima020 [189]
3 years ago
7

During which lunar phase is the moon's far side entirely lit

Physics
2 answers:
Alla [95]3 years ago
7 0
The phase where the moons far side is entirely lit is called the full moon
yulyashka [42]3 years ago
4 0
<span>During which lunar phase is the moon's far side entirely lit?</span><span>

"Near side entirely lit" means we see the whole side facing us. The moon looks like a complete circle. 

Hope This Helped! :3</span>
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belka [17]
Both mass and weight
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3 years ago
Read 2 more answers
Just need help with 1 and 2 please :D i’m having a bit of trouble :/
dexar [7]
1. Traveling by car means you have specific roads to follow. You won’t be able to go straight to Banning high from POLAHS. The 8.4km will be defined as distance. Traveling by helicopter you don’t have roads to follow that means you can fly directly to banning high. 6.8km will be defined as displacement.

2. A) 400m
B)0m
C)d=1/2(vi+vf)t
400=1/2(0+vf)92
8.7m/s
D) 0m/s
E) Not sure but instantaneous velocity refer to velocity at a given point. Average velocity is just the average. Usually instantaneous velocity won’t be same as the average velocity.
Plz like if it helped.
7 0
3 years ago
What type of energy conversion results when friction slows down a ball rolling across the floor
ale4655 [162]

Friction between the ball and the floor is stealing some of the kinetic energy of the ball, and turning it into heat.

8 0
2 years ago
A heat source could be considered a source of pollution Please select the best answer from the choices provided
jeyben [28]

The answer is true, is called Thermal pollotion:).

5 0
2 years ago
A wire of Nichrome (a nickel– chromium– iron alloy commonly used in heating elements) is 1.0 m long and 1.0 mm² in cross-se
Lyrx [107]

Answer:

The conductivity of Nichrome is 2\times 10^6\ S/m.

Explanation:

Given:

Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

Length of wire (L) = 1.0 m

Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]

We know, from Ohm's law, that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. Therefore, the resistance of the nichrome wire is given as:

R=\frac{V}{A}=\frac{2.0}{4.0}=0.5\ \Omega

Now, resistance of the nichrome wire in terms of its resistivity, length and area of cross section is given as:

R=\rho\frac{L}{A}

Where, \rho\to resistivity\ of\ Nichrome

Now, plug in all the values given and solve for \rho. This gives,

0.5\ \Omega=\rho\frac{1.0\ m}{1\times 10^{-6}\ m^2}\\\\\rho=\frac{0.5\times 1\times 10^{-6}}{1.0}=0.5\times 10^{-6}\ \Omega-m

Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:

\sigma=\frac{1}{\rho}=\frac{1}{0.5\times 10^{-6}}=2\times 10^6\ S/m

Conductivity is measured in Siemens per meter (S/m)

Therefore, the conductivity of Nichrome is 2\times 10^6\ S/m.

7 0
3 years ago
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