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2 years ago

5

two bodies of masses 10 kg and 4 kg are moving in opposite direction with the same velocity of 5 m per second if they Collide an

d stick together after the impact calculate their velocities

1 answer:

bogdanovich [222]2 years ago

3 0

Answer:

dasd

Explanation:

dsdas

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Find the work w1 done on the block by the force of magnitude f1 = 65.0 n as the block moves from xi = -3.00 cm to xf = 3.00 cm .

inn [45]

W = F•dx
F = 65 N,
dx = xf - xi = 0.03 m - (-0.03 m) = 0.06 m
W = 65 N × 0.06 m = 3.9 J

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2 years ago

A Perspex container has a 6 cm square base and contains

crimeas [40]

Answer:

a) V = 252 cm³

b) Vs = 72 cm³

Explanation:

a)

The volume of the water can be given by the following formula:

$Volume\ of\ Water = V = (Base\ Area)(Height)\\V = (Length)^2(Height)\\V = (6\ cm)^2(7\ cm)\\$

<u>V = 252 cm³</u>

<u></u>

b)

The volume of stone can be given by the change in volume of the water when the stone is dipped into it.

$Volume\ of\ Stone = Vs = (Length)^2(Change\ in\ Height\ of\ Water)\\Vs = (6\ cm)^2(9\ cm - 7\ cm)\\$

<u>Vs = 72 cm³</u>

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2 years ago

If one stand of DNA reads as AATTCCGGATCG, what would the opposite strand bases be?

3241004551 [841]

TTAAGGCCTAGC

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4 0

2 years ago

How are acceleration and speed related

Gre4nikov [31]

Answer:

Acceleration is the rate of change of velocity. Usually, acceleration means the speed is changing, but not always. When an object moves in a circular path at a constant speed, it is still accelerating, because the direction of its velocity is changing. Comment on robshowsides's post “Speed is the magnitude of velocity.

Explanation:

hope it helped tee hee

6 0

2 years ago

Read 2 more answers

The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th

Rom4ik [11]

Answer:

Approximate escape speed = 45.3 km/s

Explanation:

Escape speed

$v=\sqrt{\frac{2GM}{R}}$

Here we have

Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

R = 1 AU = 1.496 × 10¹¹ m

M = 2.3 × 10³⁰ kg

Substituting

$v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s$

Approximate escape speed = 45.3 km/s

6 0

2 years ago