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2 years ago

What is 3(k-6)=15? Please provide an explanation.

2 answers:

8 0

First you would have use the distributive property to make this an easier problem.So take 3 times k (if the variable has no number just add a one) and 3 times -6 to get the problem of 3k-18=15. Now you would add 18 to -18 and get 0 and do it on the 15. 15+18=33,now you have 3k=33.now you divide 3/3 and get 1 and divide 33 by 3 to get 11.
Answer is k=11

Mkey [24]2 years ago

5 0

I might be able to give you a hand here!

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Anestetic [448]

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2 years ago

How to solve x/3 + 4 = -2

r-ruslan [8.4K]

Answer:

x=−18

Step-by-step explanation:

Let's solve your equation step-by-step.

+4=−2

Step 1: Simplify both sides of the equation.

x+4=−2

Step 2: Subtract 4 from both sides.

x+4−4=−2−4

x=−6

Step 3: Multiply both sides by 3.

3*(

x)=(3)*(−6)

x=−18

5 0

2 years ago

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Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

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3 years ago

Solve equation by factoring.

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$x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4$

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2 years ago

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Lisa [10]

Answer:

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Step-by-step explanation:

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2 years ago

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