The formula for finding the radius of a circle while only knowing the circumference is r=C ÷ 2π. Substituting the value 10 for C, and 3.14 for π, we get:
r=10 ÷ 3.14 · 2 Now we divide 10 by 6.28
r≈1.59
A parabola is a quadratic function, and a quadratic can be expressed in vertex form, which is:
y=a(x-h)^2+k, where (h,k) is the vertex (absolute maximum or minimum point of the quadratic)
In this case we are given that (h,k) is (-5,80) so we have so far:
y=a(x--5)^2+80
y=a(x+5)^2+80, we are also told that it passes through the point (0,-45) so:
-45=a(0+5)^2+80
-45=25a+80 subtract 80 from both sides
-125=25a divide both sides by 25
-5=a, so now we know the complete vertex form is:
y=-5(x+5)^2+80
The x-intercepts occur when y=0 so:
0=-5(x+5)^2+80 add 5(x+5)^2 to both sides
5(x+5)^2=80 divide both sides by 5
(x+5)^2=16 take the square root of both sides
x+5=±√16 which is
x+5=±4 subtract 5 from both sides
x=-5±4 so the x-intercepts are:
x=-1 and -9
Answer:
1 is a
Step-by-step explanation:
Answer:
Step-by-step explanation:
In an isosceles triangle, the base angles are equal. This also means that two sides of the triangle are equal in length. Since the sum of the angles in a triangle is 180 degrees, it means that the third angle of the given triangle is
180 - (80 + 50) = 50 degrees
Therefore, the base angles of the isosceles triangle are 50 degrees each. For more triangles with these conditions to be drawn, only the lengths of the equal sides can be increased or decreased. This would in turn increase the length of the third side. Therefore, isosceles triangles of the same angles but different sizes can be drawn.
Answer:
B. 5/6
Step-by-step explanation:
5 divided by 6 equals .8333.