(i) 0.8% into a fraction

Scores for a common standardized college aptitude test are normally distributed with a mean of 493 and a standard deviation of 9

Tomtit [17]

Answer:

34.01% probability that his score is at least 532.1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 493, \sigma = 95$

If 1 of the men is randomly selected, find the probability that his score is at least 532.1.

This is 1 subtracted by the pvalue of Z when X = 532.1. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{532.1 - 493}{95}$

$Z = 0.41$

$Z = 0.41$ has a pvalue of 0.6591

1 - 0.6591 = 0.3409

34.01% probability that his score is at least 532.1.

3 0

3 years ago

The table and graph represent two different bus tours,

JulsSmile [24]

Answer: The functions have the same initial value

Step-by-step explanation: I say this because "Tour 1" is a linear funtion. I subtracted 45 from 55 and got 10, this happened for all the numbers on the table. On the other hand, When observing the graph it shows the initial point between 40 and 30. I estimated and got 35. When I went to check my answer, I subtracted 35 from 45 and got 10. Therefore, 35 is the initial value for both the graph and the chart.

6 0

3 years ago

What is the area of the following circle?

svp [43]

Answer:

50.27 is the correct answer, at least should be

3 0

4 years ago

Read 2 more answers

Isla is given $100,000 for college expenses. She deposits the money in a bank account that doesn't pay any interest on the money

BigorU [14]

Answer:

She still has $15000 in the account after she graduates

Step-by-step explanation:

Let the number of semesters is s and the balance id b(s)

<u>The balance after s semesters can be expressed as:</u>

b(s) = 100000 - 8500s

<u>After 10 semesters Isla has:</u>

b(10) = 100000 - 8500*10 = 15000

6 0

3 years ago

Solve <img src="https://tex.z-dn.net/?f=-2x%5E2%20%2B3x%20-%209%20%3D%200" id="TexFormula1" title="-2x^2 +3x - 9 = 0" alt="-2x^2

MArishka [77]

Answer:

$x= \frac{3-3\sqrt{7}i }{4}$ and $x= \frac{3+3\sqrt{7}i }{4}$

Step-by-step explanation:

We have to solve the given equation - 2x² + 3x - 9 = 0

To solve the equation given above we have to factorize the left-hand side of the equation.

But it can not be factorized. So, use the Sridhar Achaya formula.

Therefore, $x= \frac{-3 + \sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)}$ and $x= \frac{-3 -\sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)}$

So, $x= \frac{3-3\sqrt{7}i }{4}$ and $x= \frac{3+3\sqrt{7}i }{4}$ {Where $i=\sqrt{-1}$ }

Therefore, the solutions are imaginary numbers. (Answer)

Note: The Sridhar Acharya Formula gives if ax² + bx + c = 0, then the roots of the equation are $x = \frac{-b + \sqrt{b^{2}-4ac } }{2a}$ and $x = \frac{-b - \sqrt{b^{2}-4ac } }{2a}$ .

3 0

4 years ago

(i) 0.8% into a fraction​

(i) 0.8% into a fraction