Answer:
a
b

Step-by-step explanation:
From the question we are told that
The probability that an employees suffered lost-time accidents last year is 
The probability that an employees suffered lost-time accident during the current year is

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

Generally the probability that an employee will experience lost time in both year is mathematically represented as

=> 
=> 
Generally the percentage of employees that will experience lost time in both year is mathematically represented as

=> 
=>
Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

=> 
=> 
Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

=> 
=> 
Yeah It Would
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Either 7x or -3x hope this helps hun!!
Answer:
(A'B'): 3 1/2 IN.
(D'E'): 2 1/2 IN.
(R'S'): 4 IN.
Step-by-step explanation:
Just slice the numbers in half
Also i took the test.
10^1 = .2
10^2 = 2.0
10^3 = 20.0
So, the answer is 3.