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iVinArrow [24]
3 years ago
12

In the figure below, Ray BD bisects angle ABC

Mathematics
1 answer:
viva [34]3 years ago
4 0

Answer: 65 and 130

Step-by-step explanation:

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Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A? yes, be
mr_godi [17]

Answer:

yes, becoz all the elements of set R is in set A

8 0
3 years ago
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Which of the following is a true statement about the equation y= -7/8x+10
-BARSIC- [3]
First of all we can rule out that the slope is 10. The coefficient before the x term is not 10 so the answer is not a.

Following on what I said for option a, option b is correct as the coefficient before the x term is -7/8. Therefore the answer is B.

The answer is not C as when x = 0, y is not 0. This means the line does not pass through the origin (0,0)

Option D is not true aswell. When x = 1, y= 9.125. When x= 2, y= 8.25. When x=3, y= 7.375. X is increasing whereas y is decreasing. Therefore option D is ruled out.

The answer is option B.

I hope this has helped you.

Please mark as brainliest if you are happy with this explanation. Have a great day!
5 0
3 years ago
For all values of x,<br> f(x) = 2x - 6<br> and<br> g(x) = x2 + 2<br> a) Find g(3)<br> b) Find fg(3)
Stels [109]
A is 11 and b is 16. for b you would plug in what you got for a for x
4 0
2 years ago
Write the equation of the circle with center (3, 2) and (−6, −4) a point on the circle.
yulyashka [42]
The equation for a circle is as followed:

(x-h)^2+(y-k)^2=r^2

where the center of the circle is at (h,k) and the radius of the circle is r.

We are given (h,k) and need to find the radius. To do so, we can use the distance formula to find the distance from the  center to the point on the circle:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Plug in the two points:

d= \sqrt{(3-(-6))^2+(2-(-4))^2}

d= \sqrt{(9)^2+(6)^2}

d= \sqrt{117}

If the distance from the center to the edge of the circle is the square root of 117, then r^2 = 117.

The answer is:

(x-3)^2+(y-2)^2=117
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=3y%20-%205x%20%3D%2010" id="TexFormula1" title="3y - 5x = 10" alt="3y - 5x = 10" align="absmid
kompoz [17]

Answer:

\dfrac{5}{3}

Step-by-step explanation:

To find the gradient (slope) of the given <u>linear relation</u>, use <u>arithmetic operations</u> to isolate y:

Given relation:

3y-5x=10

Add 5x to both sides:

\implies 3y-5x+5x=10+5x

\implies 3y=5x+10

Divide both sides by 3:

\implies \dfrac{3y}{3}=\dfrac{5}{3}x+\dfrac{10}{3}

\implies y=\dfrac{5}{3}x+\dfrac{10}{3}

<u>Slope-intercept form of a linear equation</u>

y = mx+b

where:

  • m is the slope (gradient)
  • b is the y-intercept

Comparing the rewritten equation with the slope-intercept formula, the gradient (slope) of the given linear relation is ⁵/₃.

Learn more about linear equations here:

brainly.com/question/27317293

brainly.com/question/27781455

7 0
1 year ago
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