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Naddika [18.5K]
3 years ago
15

Which characteristic is found in liquids and gases? A. Has a fixed volume B. Particles stay in a fixed position C. No particle m

ovement D. Takes the shape of the container
Chemistry
2 answers:
STALIN [3.7K]3 years ago
6 0

Answer:

The answer to your question is letter D.

Explanation:

A. Has a fixed volume This is not the right answer, liquids and gases take the shape of the container in which they are.

B. Particles stay in a fixed position This answer is wrong, this characteristic is  of solids but not of liquids and gases.

C. No particle movement This characteristic is also of solids, in liquids and gases the particles can move.

D. Takes the shape of the container. This is the right answer, liquids and gases take the shape of the container.

anzhelika [568]3 years ago
3 0

Answer:

D :)

Explanation:

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Carvone is a substance that occurs in two forms having different arrangements of the atoms but the same molecular formula (c10h1
Korvikt [17]

The molecular mass of Carvone is calculated as;

                          =  12 (C)₁₀  +  1.008 (H)₁₄  +  16 (O)

                          =  120  +  14.112  +  16

                          =  150.112

%age of Carbon;

                          =  (120 ÷ 150.112) × 100

                          =  79.94 %

%age of Hydrogen;

                          =  (14.112 ÷ 150.112) × 100

                          =  9.40 %

%age of Oxygen;

                          =  (16 ÷ 150.112) × 100

                          =  10.65 %

7 0
3 years ago
HNO3 + KOH + H2O + KNO3<br><br> ACID:<br> BASE:<br> SALT:
SSSSS [86.1K]

Explanation:

acid, HNO3

base, KOH

salt ,KNO3

4 0
2 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
) write the balanced equation for the reaction that occurs when methanol, ch3oh (l), is burned in air. what is the coefficient o
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2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(g)

k(O₂)=3
3 0
3 years ago
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prisoha [69]
47.867 u ± 0.001 u lol
8 0
3 years ago
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