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insens350 [35]
3 years ago
6

Nitrogen-fixers are the critical links between ______.

Chemistry
2 answers:
bija089 [108]3 years ago
8 0

Answer:

a

Explanation:

Lisa [10]3 years ago
3 0
Correct answer to your question is A
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What is the ph of a 0.0055 m ha (weak acid) solution that is 8.2% ionized?
Trava [24]
Answer is: pH value of weak is 3.35.
Chemical reaction (dissociation): HA(aq) → H⁺(aq) + A⁻(aq).
c(HA) = 0.0055 M.
α = 8.2% ÷ 100% = 0.082.
[H⁺] = c(HA) · α.
[H⁺] = 0.0055 M · 0.082.
[H⁺] = 0.000451 M.
pH = -log[H⁺].
pH = -log(0.000451 M).
pH = 3.35.
pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity <span>an aqueous solution.</span>
3 0
3 years ago
A geological process (2 points)
densk [106]
They are all correct good job bud I hope it helps and good luck

4 0
3 years ago
Read 2 more answers
State Hess' law of constant heat summation.
AveGali [126]

Answer:

-74.6 kj/mol

Explanation:

you can see the answer at the pic

8 0
3 years ago
5. A hollow glass sphere has a volume of 350 mL and
Rina8888 [55]

Explanation:

Given that,

Volume of a hallow glass sphere is 350 mL

Specific gravity is 1.252

We need to find the weight of the sphere. The ratio of density of substance to the density of water is called specific gravity.

The density of water is 1 g/mL

\text{specific gravity}=\dfrac{\text{density of substance}}{\text{density of water}}\\\\SG=\dfrac{m}{V\times \rho_w}\\\\m=SG\times V\times \rho_w\\\\m=1.252\times 350\ mL\times 1\ g/mL\\\\m=438.2\ \text{grams}

We know that,

1 pound = 453.592 grams

So,

m = 0.97 lbs

So, the weight of the sphere is 0.97 lbs or 0.97 pounds.

5 0
3 years ago
Suppose you have a 2.0 molar solution of sodium hydroxide (naoh), and you need 65 ml of 0.6 molar naoh. how should you make this
nalin [4]

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

65mL*\frac{1L}{1000mL} =0.065L

Calculating the moles of NaOH in the final solution:

0.065L * \frac{0.6 mol}{L} =0.039mol

Finding out the volume of 2.0 M solution taken to prepare the final solution:

0.039 mol * \frac{1L}{2.0mol}=0.0195L*\frac{1000mL}{1L} =19.5mL

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.


3 0
3 years ago
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