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zysi [14]
3 years ago
12

Which statement describes an arrhenius acid?

Chemistry
2 answers:
enot [183]3 years ago
7 0
The statement that would beat describe an Arrhenius acid would be the second Option. It produces H+ ions in solution. The other definitions would be suitable for Arrhenius base, Bronsted Lowry Acid/Base, and Lewis Base.
mixer [17]3 years ago
4 0

Answer: it produces H^+ in solution  

Explanation:-

According to Arrhenius concept, an acid is defined as a substance which donates hydrogen ions (H^+) in water and a base is defined as a substance which donates hydroxide ions (OH^-) when dissolved in water.

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

Arrhenius acid: HCl\rightarrow H^++Cl^-

Arrhenius base: NaOH\rightarrow Na^++OH^-

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(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
Elements are organized on the periodic table based on their properties. Which statement correctly predicts and explains the chem
Elanso [62]

Answer is: a. Rubidium (Rb) is more reactive than strontium (Sr) because strontium atoms must lose more electrons.

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).  

Alkaline metals (group 1), in this example rubidium, have lowest ionizations energy and easy remove valence electrons (one electron), they are most reactive metals.

Earth alkaline metals (group 2), in this example strontium, have higher ionization energy than alkaline metals, because they have two valence electrons, they are less reactive.  

Rubidium electron configuration: ₃₇Rb 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s¹; one valence electron is 5s¹ orbital.

Strontium electron configuration: ₃₈Sr 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s²; two valence electrons is 5s² orbital.

7 0
3 years ago
Read 2 more answers
Identify the species that was reduced in the titration reaction. Justify answer in terms of oxidation number 6h+(aq)+2mno4−(aq)+
egoroff_w [7]

Answer:

Explanation:

Reaction given

6 H⁺ + 2 MnO₄⁻ + 5 (COOH)₂ = 10CO₂ +8H₂O + 2 Mn⁺²

Oxidation number of Mn in MnO₄⁻

=  x - 4 x 2 = -1

x = 8 -1

+ 7

Oxidation no of Mn in Mn⁺² =  +2

So its oxidation no is decreased from + 7 to + 2  . Hence it is reduced.

5 0
3 years ago
In a chemical reaction,_______________are the substances present after the reaction.
dsp73

Answer:

In a chemical reaction, <u>products</u> are the substances present after the reaction

8 0
2 years ago
Read 2 more answers
How to find an experimental error
gulaghasi [49]
Divide the difference by the accepted value and <span> Multiply times 100 to make the value a percent. Use significant figures in all your calculations. When you subtract (Step #1) round your answer to the correct number of significant figures.</span> 
6 0
3 years ago
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