So first you work out the ratio. The formula tells us that for every one 'amount' of Ca and Cthere will be 3x the amount of oxygen. So, the ratio is 1:1:3, (=5) therefore 70g divided by 5 = 14.
If 70g of CaCO3 is heated there will be (1x14) 14g Ca, (1x14) 14g C and (3x14) 42g of O.
Weight of CaO= 42+14, 56g
(I hope this is right! Good luck xx)
Answer: 1. 10% is used to live 30% is stored.
2. an educated guess.
Explanation:
The decomposition of CCl4 is as follows:
CCl4 (g) ---> C(s) + 2Cl2 (g) Kp = 0.76
where Kp = (PCl2)^2 / (P_CCl4)
P_C is zero since carbon is in solid form.
Express P_CCl4 in terms of P_Cl2
0.76 = (P_Cl2)^2 / (P_CCl4)
0.76P_CCl4 = (P_Cl2)^2
Ptotal = P_Cl2 = 1.9 atm
Solve for P_CCl4
P_CCl4 = 4.75 atm<span />
