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stiks02 [169]
3 years ago
6

SOS helppppppppppppp has

Chemistry
1 answer:
prisoha [69]3 years ago
8 0
47.867 u ± 0.001 u lol
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Suppose a 10.0 mL sample of an unknown
mote1985 [20]

The concentration of HCl is equal to 2.54mol/L.

<h3>Mole calculation</h3>

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

                                               M = \frac{mol}{v}

Thus, to find the molarity of the sample, the following calculations must be performed:

V_f = 10ml + 625ml = > 635ml

                                              \frac{0.004mol}{xmol} =\frac{1000ml}{635ml}

                                                 x = 0.00254 mol

So, 0.00254 moles were added per 10ml, so we can do:

                                              \frac{0.00254mol}{xmol}= \frac{10ml}{1000ml}  \\x = 2.54mol/L

So, the concentration of HCl is equal to 2.54mol/L.

Learn more about mole calculation in: brainly.com/question/2845237

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How do trees stay please help
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