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3 years ago

Sam’s basketball team won 70% of the games they played. How many games did they win?

2 answers:

7 0

Assuming it’s out of 100 it would 70 games they have won, but if it provides a number you will need to provide that for the correct answer.

Anastaziya [24]3 years ago

3 0

Answer:

Step-by-step explanation:

Its impossible to tell from your question because there is no other value that I can find 70% of. I need to know how many games were played in the first place in order to find 70 percent of it.

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Fay has a lemonade stand. She spends £35 on ingredients. She sells each glass of lemonade for £2.10. If she sells 50 glasses of

Zarrin [17]

Answer:

£70.00

Step-by-step explanation:

You basically want to find what she spent in total, then subtract the amount she spent on ingredients.

50 glasses of lemonade at £2.10 each would be £105. (50*2.1)

Subtract the cost of ingredients, which is £35, with the total she made, £105, to get £70 (105-35)

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3 years ago

Multiply and simplify: -3ab^3 • (-4a^4b^5)

grandymaker [24]

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3 years ago

Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f

Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

$P(A) = 0.1*0.8 + 0.25*0.2 = 0.13$

Probability that a student is foreign and undergraduate:

10% of 80%. So

$P(A \cap B) = 0.1*0.8 = 0.08$

What is the probability that the student is an undergraduate?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154$

0.6154 = 61.54% probability that the student is an undergraduate

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3 years ago

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3 years ago