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aleksandr82 [10.1K]
3 years ago
14

The following data are from a completely randomized design.

Mathematics
1 answer:
Mila [183]3 years ago
7 0

Answer:

a)1488

b) 744

c) 2030

d) 135.333

e) see attached table

f) There is sufficient evidence to reject the claim of equal means.  

Step-by-step explanation:

a) Determine the value of total-group variability SS(tot):

SS(tot)=∑x^2(tot)-(x(tot))^2/N=376766-2592^2/18 ≅ 3518

Determine the value of the sum of squares between groups:  

SS(bet) = ∑_(all groups) (∑x_i)^2/n_i -(∑x(tot))^2/N

            =936^2/6+852^2/6+804^2/6-2592^2/6≅ 1488

b) d.f(BET) is the number of groups k decreased by 1.  

d.f(BET) = k - 1= 3-1 = 2

MS(BET) is SS(BET) divided by d.f(BET):

MS(BET)=SS(BET)/ d.f(BET)

               =1488/2

               =744

c) The value of the sum of squares within groups (due to error) is then the value of the total-group variability decreased by the value of the sum of squares between groups (Note: using this calculation you then immediately obtain that the sum SS(tot) =SS(bet)+ SS(W) holds):  

SS(W) = SS(tot) - SS(bet) = 3518 - 1488 = 2030

d)  d.f.w is the total sample size decreased by the number of groups k.  

  d.f.w = N — k = 18 — 3 = 15

MSw is SSw divided by d.f.w:  

MSw =SSw/d.f.w=2030/15=135.333

e) see attached table

f) The value of the test statistic F is then MS(BET) divided by MSw:

F=MS(BET)/MSw=744/135.3333≅5.5

The degrees of freedom are the same as those for between groups and within groups:  

d.f.N=d.f(BET)=2

d.f.D=d.f.w=15

The P-value is the probability of obtaining the value of the test statistic, or a value more extreme. The P-value is the number (or interval) in the column title of Table 4 containing the F-value in the row dfn = 2 and dfd = 15:  

0.01<P<0.025

If the P-value is less than the significance level, reject the null hypothesis.  

P<0.05==> Reject H_o

There is sufficient evidence to reject the claim of equal means.  

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Answers:

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Answer:

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The required model for the situation is m=25d

The table is shown below:

Step-by-step explanation:

Consider the provided information.

Joshua spends 25 minutes of each day reading. Let d be the number of days that he reads, and let m represent the total minutes of reading.

We need to determine which variable is independent and which is dependent.

Here, the number of days are independent and the total number of minutes are dependent.

If he spends 25 minutes each day. So the total number of minutes in d days are:

m=25d

The required model for the situation is m=25d

Now make the table which showing the number of minutes spent reading over 7 days.

Substitute the value of d from 1 to 7 in m=25d

Number of days(D)        Minutes(M)

          1                                 25

          2                                 50

          3                                 75

          4                                 100

          5                                 125

          6                                 150

          7                                 175

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The inequality 10.45b + 56.50 &lt; 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceedin
nordsb [41]

Question :

The inequality 10.45b + 56.50 < 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceeding the weight limit of the truck. The solution is written as {b | b < 22.6}. Which statement best describes the meaning of the solution?

The truck can hold more than 22 boxes.

The truck can hold more than 23 boxes.

The truck can hold up to 22 boxes.

The truck can hold up to 23 boxes.

Answer:

Option C: The truck can hold up to 22 boxes.

Explanation:

Given that the inequality is 10.45b + 56.50 < 292.67 is used to find the number of boxes can be loaded on a truck without exceeding the weight limit of the truck.

To determine the number of boxes, let us solve the inequality.

Thus, we have,

10.45b + 56.50 < 292.67

Subtracting both sides by 56.50, we get,

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Dividing both sides by 10.45, we have,

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Therefore, the truck can hold up to 22 boxes.

Hence, Option C is the correct answer.

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