Answer:
Heterozygous dominant (Bb) and homozygous recessive (bb)
Explanation:
This cross involves the gene that codes for color blindness in whales. The allele for no color blindness/normal vision (B) is dominant over the allele for color blindness (b). This means that B will mask the phenotypic expression of b in a heterozygous state (Bb).
According to the question, one of the parents is color blind meaning it possesses the homozygous recessive genotype (bb) while the other parent (pearl) has a normal vision which can either be homozygous dominant or heterozygous dominant since the normal vision allele (B) is dominant.
However, since one of the two offsprings (sons) is also color blind, this implies that the parent with normal vision is heterozygous i.e. contains both dominant and recessive alleles, for the trait. What happens is that, when a bb and Bb parent are crossed, they produce gametes with either a recessive or dominant allele.
The Bb produces gametes with B and b alleles while the bb produces gametes with b and b alleles. When this are crossed using a punnet square, four possible offsprings will be produced with two distinct genotypes: Bb and bb. Hence, this means that there is a 1/2 chance of producing an offspring with the recessive trait from this cross as the case is in the whales.
Answer:
The second answer choice.
Explanation:
Genetic variation must be the answer as the plants were grown in the same conditions. Therefore, the only source of variability might be genetic variation.
The first choice is not the answer because Genetic factors cannot cause the environment around the plant to change.
The third choice is not the answer because the Environmental factors are the same, and if they were really to cause a mutation, all three plants would mutate.
The fourth is the same reason as the third: if environemnt conditions affected the flower, all three plants would change color since they were all grown in the same environemnt, not just the one we see in the results.
Answer:
B. 3
Explanation:
Mitosis is the process of reproduction of somatic/body cells. This means that the number of chromosomes the original (parent) cell started out with, will remain the same for the daughter cells.
Given that if a parent cell has 3 chromosomes before mitosis, then the 2 daughter cells produced will also have 3 chromosomes after mitosis and cytokinesis.
Answer:
B:U = 1:20
Explanation:
Let the number of broken eggs be B.
Let the number of unbroken eggs be U.
Given the following data;
Number of crates of egg = 10 crates
But, 1 crate of egg = 30 eggs
10 crates of egg = 30 * 10 = 300 eggs
B = 15 eggs
U = 300 eggs
Ratio B to U = B:U
B:U = 15:300
Dividing by 15, we have;
B:U = 1:20
