Hello:
ln(2e^3x) =ln2+lne^3x
<span> =ln2 +3xlne
= ln2+3x .....lne=1
</span><span>choice B</span>
Answer:
Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.
Step-by-step explanation:
We are given the following information in the question:

where μ is the average amount of money in a savings account for a person aged 30 to 40.
Type I error:
- Type I error is also known as a “false positive” and is the error of rejecting a null hypothesis when it is actually true.
- In other words, this is the error of accepting an alternative hypothesis when the results can be attributed by null hypothesis.
- A type I error occurs during the hypothesis testing process when a null hypothesis is rejected, even though it is correct and should not be rejected.
Thus, in the above hypothesis type error will occur when we reject the null hypothesis even when it is true.
Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.
All reals numbers from 0 to 200, inclusive.
Answer:
1001/1500
Step-by-step explanation:
The easiest method for doing this is to just average the two numbers.
e.g. to find a number x between the two numbers ab and cd
x=12[ab+cd]
=12[adbd+bcbd]
=ad+bc2bd
In this case…
x=(2×5)+(3×4)2×2×5=10+1230=2230=1115
You can easily see where that came from.
23=1015 and 45=1215
and the ‘common denominator’ means you just have to pick a value between 10 and 12 . i.e. 11
But you can also say…
23=100150 and 45=120150
and choose any of 101150,102150,...,119150
or
23=10001500 and 45=12001500
and choose any of 10011500,10021500,...,11991500